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Vsevolod [243]
3 years ago
5

You are walking along a small country road one foggy morning and come to an intersection. while you are crossing, you hear an am

bulance siren. as a paramedic, you know that the siren sounds at a frequency of 5.87 khz. but, as an amateur musician with perfect pitch, you can tell that the frequency you are hearing is actually 5.29 khz. is the ambulance moving toward or away from you?
Physics
1 answer:
monitta3 years ago
6 0
You're hearing a higher frequency than the sound that's actually coming from the siren on the ambulance, so it must be moving TOWARD you.
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UUA, UUG, CUU, CUC, CUA and CUG
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Calculate the monentun pf 75 kg bicycle and boy who has ghe velocitg of 3m/s
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Explanation:

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Stella [2.4K]

Answer:

Somewhere between the two wires, but closer to the wire carrying λ₂

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Electric Field for a point at distance x from an electric charge Q is Ef = K*Q/x².

Electric Fied due to an electric charge is a vector and its direction is  such that  if we place a positive charge in the point it will be rejected ( equal sign charge repulse each other and different attract each other)

According to that previous explanation, it is no possible two have Ef=0 out of the two wires region, since above the upper wire and below the lower wire we have to add the two electric fields (both have the same direction). Therefore we only have possibilities of Ef = 0 inside the two wires, where the repulsion produced over a positive charge due to the two wires  are opposite

In the particular case in which λ₁ and λ₂ are equals then all the points exactly in the middle of d (distance between the two wires ) will have Ef =0.

As we can see at the beginning of the step by step explanation Electric field is proportional to the electric charge, or for a bigger charge, bigger Ef (keeping constant distance). In our case λ₁ >λ₂ then E₁ (Electric field produced by a wire carrying λ₁ will be bigger than (Electric field produced by wire carrying λ₂ at the middle way between the wires.

But for points closer to wire with λ₂  ( where E₂ is bigger than E₁ ) we will surely find an appropriate distance  to get equals E and then Ef = 0

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2 years ago
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The answer is A.

t = ( 2h / g )^1/2 = ( 2 x 6.4 / 9.8 )^1/2 = 1.14s

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