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svp [43]
3 years ago
9

Which resources are significantly polluted by heavy metals like mercury? A. soil B. water C. neither A nor B D. both A and B

Chemistry
1 answer:
Firdavs [7]3 years ago
6 0

Answer: The correct answer is option D.

Explanation:

Mercury is occurs in earth crust but its mining ,combustion of fossil fuel and extraction had led to spreading of mercury pollution not only on lands but in air and water bodies also.  

Mercury settled on land get washed way into water bodies which further gets introduced in life process of living beings in the water and eventually effecting the whole food chain or web.

Hence, from the the given options the correct option is (D).

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How many moles of H2O will be formed from the reaction of 80 g of
Roman55 [17]

Answer: 2 moles of H_2O will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles

The balanced chemical equation is:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to stoichiometry :

2 moles of NaOH give = 2 moles of H_2O

Thus 2 moles of NaOH give =\frac{2}{2}\times 2=2moles of H_2O

Thus 2 moles of H_2O will be formed.

4 0
2 years ago
Se tiene un litronde solucion de agua con alcohol con una consentracion del 4.5% v/v ¿Cuanto alcohol se tiene en la solución
Vinvika [58]

Answer:

45 mL

Explanation:

Tenemos los siguientes datos:

V = 1 L

C = 4,5% v/v

El porcentaje en volumen (%v/v) expresa el volumen de soluto (alcohol en este caso) que hay cada 100 mL de solución. Si la solución tiene una concentración del 4,5% v/v eso quiere decir que hay 4,5 ml de alcohol cada 100 ml de solución, de acuerdo a lo siguiente:

4,5% v/v alcohol = volumen alcohol/ volumen solución x 100 = 4,5 mL alcohol/100 mL solución= 4,5 mL alcohol/0,1 L alcohol

Por lo tanto, al multiplicar por el volumen total de la solución (1 L), obtenemos la cantidad total de alcohol:

4,5 mL alcohol/0,1 L alcohol x 1 L = 45 mL

3 0
3 years ago
Brian has an object suspended in the air. It has a mass of 100 kg and is 25 meters above the ground. What is the object’s potent
MatroZZZ [7]
The answer is 24500 joule
7 0
3 years ago
Read 2 more answers
A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 ml of 0.106 m naoh. calculat
Jet001 [13]
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions.  So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3. 
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole.  So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
6 0
3 years ago
Help i just need people to answer the question today
yKpoI14uk [10]

Answer:

1) Hydrogen

2) Methane

3) Carbon

4) Structural isomer

5) Ethene also known as ethylene

6) Hydrocarbons are widely used as fuel

7) Crude oil

Explanation:

6 0
3 years ago
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