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Ierofanga [76]
3 years ago
5

Solve the system of equations by elimination. HELP ASAP!!

Mathematics
2 answers:
tigry1 [53]3 years ago
5 0

Answer:

z = 4/7 y=9/14 x =27/14

viva [34]3 years ago
4 0

Answer:

x = 1, y = -1, z = 0.

Step-by-step explanation:

3x − y − 2z = 4

x + y − z = 0

2x − y + 3z = 3

Add the first and second equation (to eliminate y):

4x - 3z = 4          (A)

Add the second  and third equation (to eliminate y):

3x + 2z = 3          (B)

Multiply equation A by 2 and equation B by 3:

8x - 6z = 8

9x + 6z = 9      Adding:

17x = 17

x = 1

Substitute x = 1 in equation A:

4(1) - 3z = 4

-3z = 0

z = 0.

Now substitute x = 1 and z = 0 in the first equation:

3(1) - y - 2(0) = 4

-y =  4 - 3

-y = 1

y = -1.

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