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3 years ago

Which statements accurately describe the motion map?

Physics

2 answers:

ahrayia [7]3 years ago

3 0

Answer: B & D

Explanation:

Naddika [18.5K]3 years ago

3 0

B AND D YOUR WELCOME CUZ

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A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init

Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

$h=\frac{gt^2}{2}$

For second stone

$h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}$ ---2

Equating 1 &2 we get

$\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}$

$\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0$

$13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0$

$26.46t-35.721-52.92t+142.884=0$

$t=4.05 s$

4 0

3 years ago

We beat a blanket with a stick to remove dust particles why

lutik1710 [3]

Answer:

removing the dust particles cleans the blanket

6 0

3 years ago

Find the kinetic energy K of a satellite with mass m in a circular orbit with radius R. Express your answer in terms of m, M, G,

ratelena [41]

Answer:

$K=\frac{GmM}{2R}$

Explanation:

The kinetic energy is defined as:

$K=\frac{mv^2}{2}(1)$

Here, m is the object's mass and v its speed. In this case the speed of the satellite is the orbital speed, which is given by:

$v_{orb}=\sqrt\frac{GM}{R}(2)$

Here, G is the gravitational constant, M is the mass of the object that the satellite is orbiting and R is the radius of its circular orbit. Replacing (2) in (1):

$K=\frac{mv_{orb}^2}{2}\\K=\frac{m(\sqrt\frac{GM}{R})^2}{2}\\K=\frac{GmM}{2R}$

3 0

4 years ago

A scientist counts the number of bacteria colonies growing in each of six lab dishes.

Vsevolod [243]

Hi!

The correct answer is: C. It is the data value that appears the most often in the set.

<h3>Explanation</h3>

The mode of a set of values is the number which is the most frequently appearing, or most repeating value in the range. The numbers that show one time each are

A - 16 , C - 25 , D - 3

While 13 appears three times with the dishes labelled

B , E and F

So, the value that appears the most times is 13, and hence 13 is taken as the mode of this data set

<h3>Hope this helps!</h3>

5 0

3 years ago

Read 2 more answers

Positive Charge is distributed along the entire x axis with a uniform density 12 nC/m. A proton is placed at a position of 1.00

lions [1.4K]

Answer:

b. $\Delta KE = 390 eV$