2 years ago

Which statements accurately describe the motion map?

Physics

2 answers:

ahrayia [7]2 years ago

3 0

Answer: B & D

Explanation:

Naddika [18.5K]2 years ago

3 0

B AND D YOUR WELCOME CUZ

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If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, aft

elena-14-01-66 [18.8K]

Since the object is dropped from some height so its initial speed must be zero

acceleration of the object is due to gravity

so we can use kinematics to find the time it will take to drop by x = 22 m

$\delta x = v_i * t + \frac{1}{2}at^2$

$22 = 0 + \frac{1}{2}*9.8*t^2$

$t = 2.12 s$

Now the speed after 2.12 s will be given as

$v_f = v_i + at$

$v_f = 0 + 9.8 * 2.12$

$v_f = 20.8 m/s$

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2 years ago

The lower the frequency the _____ the pitch sound.

stepan [7]

The lower the frequency the lower the pitch sound.

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2 years ago

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Explain why it is easier to climb a mountain on a zigzag path rather than one straight up the side.

GaryK [48]

Although a zig zag pattern going up a mountain means you walk further, the incline of the slope is a lot less so you don't have to work as hard.

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2 years ago

The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth's surfac

andrezito [222]

Answer:

$E=8.13\times 10^{12}\ J$

Explanation:

Given that,

The mass of a Hubble Space Telescope, $m_1=1.16\times 10^4\ kg$

It orbits the Earth at an altitude of $5.68\times 10^5\ m$

We need to find the potential energy the telescope at this location. The formula for potential energy is given by :

$E=\dfrac{Gm_1m_e}{r}$

Where

$m_e$ is the mass of Earth

Put all the values,

$E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J$

So, the potential energy of the telescope is $8.13\times 10^{12}\ J$ .

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2 years ago

two long parrallel wires that are 0.30 m apart carry currents of 5.0 A and 8.0 A in the opposite direction.Find the magnitude of

Vera_Pavlovna [14]

Answer: The magnitude of force per length that each wire exert on the other wire is 2.67×10^-5 N/m.

The force is repulsive.

Explanation: Please see the attachments below

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2 years ago