Answer:
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<h3>
Answer:</h3>
18.9 g F₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.00 × 10²³ molecules F₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of F₂ (Diatomic) - 38.00 g/mol
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%203.00%20%5Ccdot%2010%5E%7B23%7D%20%5C%20molecules%20%5C%20F_2%28%5Cfrac%7B1%20%5C%20mol%20%5C%20F_2%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20molecules%20%5C%20F_2%7D%29%28%5Cfrac%7B38.00%20%5C%20g%20%5C%20F_2%7D%7B1%20%5C%20mol%20F_2%7D%29)
- Multiply:
![\displaystyle 18.9306 \ g \ F_2](https://tex.z-dn.net/?f=%5Cdisplaystyle%2018.9306%20%5C%20g%20%5C%20F_2)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
18.9306 g F₂ ≈ 18.9 g F₂
D is the answer. You cannot say that anyone is good at anything because it doesn't say that. And they were surveying the class of 2010
I have a helpful trick for such problems.
Step 1:
Write the equation asked with exact moles given in question,
PCl₃ + Cl₂ → PCl₅ --------(1)
Step 2:
Write equations given in data along with energies,
P₄ + 6Cl₂ → 4PCl₃ Δ<span>H = −1280 kj -----(2)
</span>
P₄ + 10Cl₂ → 4PCl₅ ΔH<span> = −1774 kj -----(3)
Step 3:
Compare the equation 1 with eq 2 and 3 and modify eq 2 and 3 according to eq 1 both in terms of reactant and product and number of moles. For example in eq 1 PCl</span>₃ is on left hand side and its number of moles is one, so, modify eq, 2 according to eq 1 both in terms of moles and reactant product sides. i.e.
By inter converting eq 2, the sign of energy will change from negative to positive, and divide eq 2 with 4, to have its ratio's equal to eq 1
PCl₃ → 1/4 P₄ + 1.5 Cl₂ ΔH = +320 KJ
Same steps are done for eq 3, but in this case signs are not changed only moles are changed
1/4P₄ + 2.5Cl₂ → 1/4PCl₅ ΔH = −443.5 kj
Now,
Compare both last equations,
PCl₃ → 1/4 P₄ + 1.5 Cl₂ ΔH = +320 KJ
1/4P₄ + 2.5Cl₂ → 4/4PCl₅ ΔH = −443.5 kj
_____________________________________________
PCl₃ + Cl₂ → PCl₅ ΔH = -123.5 KJ
<span>Dominant traits are traits that will be expressed. Recessive traits are traits that are never expressed in the presence of a dominant trait. They can only be expressed when both alleles are recessive.
This is true.
Dominant traits are just that - dominant. If they are present in the genotype, they will appear in the phenotype.</span>