Y = -2(x - 1)² + 8
y = -2((x - 1)(x - 1)) + 8
y = -2(x² - x - x + 1) + 8
y = -2(x² - 2x + 1) + 8
y = -2(x²) + 2(2x) - 2(1) + 8
y = -2x² + 4x - 2 + 8
y = 2x² + 4x + 6
2x² + 4x + 6 = 0
x = <u>-4 +/- √(4² - 4(2)(6))</u>
2(2)
x = <u>-4 +/- √(16 - 48)</u>
4
x = <u>-4 +/- √(-32)
</u> 4<u>
</u>x = <u>-4 +/- 5.6568i
</u> 4
x = -4 +/- 1.4142i
x = -4 + 1.4142i x = -4 - 1.4142
y = -2x² + 4x + 6
y = -2(-4 + 1.4142i)² + 4(-4 + 1.4142i) + 6
y = -2((-4 + 1.4142i)(-4 + 4.4142i) - 16 + 5.6568i + 6
y = -2(16 - 5.6568i - 5.6568i + 1.99996164i²) - 16 + 5.6568i + 6
y = -2(16 - 11.3136i + 1.9996164) - 16 + 5.6568i + 6
y = -32 + 22.6272i - 3.99992328 - 16 + 5.6568i + 6
y = -32 - 3.99992328 - 16 + 6 + 22.6272i + 5.6568i
y = -35.99992328 - 16 + 6 + 28.284i
y = -51.99992328 + 6 + 28.284i
y = -45.99992328 + 28.284i
(x, y) = (-4 + 1.4142i, -45.99992328 + 28.284i)
y = -2x² + 4x + 6
y = -2(-4 - 1.4142i)² + 4(-4 - 1.4142i) + 6
y = -2((-4 - 1.4142i)(-4 - 1.4142i)) - 16 - 5.6568i + 6
y = -2(16 + 5.6568i + 5.6568i + 1.99996164i²) - 16 - 5.6568i + 6
y = -2(16 + 11.3136i + 1.99996164) - 16 - 5.6568i + 6
y = -32 - 22.6272i - 3.99992328 - 16 - 5.6568i + 6
y = -32 - 3.99992328 - 16 + 6 - 22.6272i - 5.6568i
y = -35.99992328 - 16 + 6 - 28.284i
y = -51.99992328 + 6 - 28.284i
y = -45.99992328 - 28.284i
(x, y) = (-4 - 1.4142i, -45.99992328 - 28.284i)
zeros: -4 + 1.4142i or -4 - 1.4142i
vertex: (-4 + 1.4142i, -45.99992328 + 28.284i) and (-4 - 1.4142i, -45.99992328 - 28.284i)
axis of symmetry: 0 + 2.8284i
<u />
3(2x + 6) hope this helps
Mali’s isn’t dndjdkdkdjdjdhjdjdjd
It would b square root of 29
Painted Area: 72 in^2
Unpainted Border on all sides: ====> 4 in"
4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 = 72
Answer: =====> 66 inches
My Internet kept messing up on me here, but the Answer is 66 inches, Sorry I couldn't finish working out the problem, going to check out my internet. - Thanks - P.
Hope that helps!!!! : )