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Natali [406]
3 years ago
15

Find the magnitude of the resultant of forces 6N and 8N acting at 240° to each other

Physics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

magnitude of the resultant of forces is 11.45 N

Explanation:

given data

force F1 = 6N

force F2 = 8N

angle = 240°

solution

we get here resultant force that is express as

F(r) = \sqrt{F_1^2+F_2^2+2F_1F_2cos\ \theta}    ..............1

put here value and we get

F(r) = \sqrt{6^2+8^2+2\times 6\times 8 \times cos240}

F(r) =  11.45 N

so magnitude of the resultant of forces is 11.45 N

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A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 s
AlekseyPX

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

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3 years ago
When an object absorbs light energy, it reflects
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VashaNatasha [74]
Question three is C and question 4 is b

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A 3047.8 kg truck has lost its brakes coming down a mountain. Fortunately, there is a ramp of thick gravel inclined at 9.5 degre
Yuliya22 [10]

Answer:

The work done by the gravel to stop the truck is 520.44 kJ

Explanation:

<u>Step 1</u>: Data given

Mass of the truck = 3047.8 kg

The ramp has an angle of 9.5 °

Velocity of  the truck = 20.68 m/s

distance = 26.6 meters

<u>Step 2:</u> Calculate initial kinetic energy

sin 9.5° = 0.165

h = ℓ*sin 9.5° = 26.6*0.165= 4.39 m

Ek = 1/2m*Vo² = 1/2*3047.8*20.68² = 651714.7 Joule = 651.7 kJ  = initial kinetic energy

<u>Step 3: </u>Calculate potential energy

Epot = U = m*g*h = 3047.8*9.81*4.39 = 131256.25 Joule = 131.26 kJ

<u>Step 4:</u>  What work is done by the truck on the gravel?  

Frictional energy Ef = 651.7 kJ - 131.26 kJ = 520.44 kJ

5 0
3 years ago
Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?
Nostrana [21]
The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2)  where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span> 
5 0
3 years ago
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