Find the magnitude of the resultant of forces 6N and 8N acting at 240° to each other

Physics

1 answer:

Alexxx [7]3 years ago

6 0

Answer:

magnitude of the resultant of forces is 11.45 N

Explanation:

given data

force F1 = 6N

force F2 = 8N

angle = 240°

solution

we get here resultant force that is express as

F(r) = $\sqrt{F_1^2+F_2^2+2F_1F_2cos\ \theta}$ ..............1

put here value and we get

F(r) = $\sqrt{6^2+8^2+2\times 6\times 8 \times cos240}$

F(r) = 11.45 N

so magnitude of the resultant of forces is 11.45 N

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