This is an example Newton's Third Law. All the kinectic energy from the moving car transferred the potential energy of the parked car. This potential is not much since the brakes are on (hopefully) and it's not in a non-moving position.
Answer:
B
Explanation:
hair can be a safety hazard
To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.
The altitude is,

And the velocity can be written as,


From the properties of standard atmosphere at altitude z = 20km temperature is



Velocity of sound at this altitude is



Then the Mach number



So front stagnation temperature



Therefore the temperature at its front stagnation point is 689.87K
The height is zero.
That means whatever place is your reference for height measurement,
the object is lying right there at that height.
Answer:
D. To ensure common resources are not overused
Explanation:
- The article of the antarctic treaty VII provides that all the consultative parties have a right to designate the observers and to undertake the inspection as of the protocol 14 of that provides the protection of the environment and to safeguard the ecological system.
- Since 1963, about 9 inspections have been conducted by the teams by visiting the stations, facilities, the vessels, and the protected areas across a wide area of East Antarctica, The most recent Antarctica expedition treaty inspection was done in Dec 2016.