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loris [4]
3 years ago
6

Your classmate states that only precious minerals, such as diamonds, are valuable. Based on your lesson on the rock cycle, you _

____.
A.agree with her; pound for pound, diamonds cost the most
B.agree with her; diamonds are valuable, but there are other minerals that are used in industry that have a high value, as well
C.disagree with her; the cost of diamonds has dropped sharply over the past ten years
D.disagree with her; diamonds have no true value
Physics
2 answers:
butalik [34]3 years ago
8 0

The correct answer is B.agree with her; diamonds are valuable, but there are other minerals that are used in industry that have a high value, as well

Diamonds are valuable but there are also many minerals that are used in Industry and are valuable too. For example Gold is a valuable element that is used in the production of Micro-processors. Platinum is another mineral that is used in the production of Catalytic converters and nitric acid. It is also very expensive.

FinnZ [79.3K]3 years ago
4 0
B, agree with her but there are other minerals that are used that have a high value as well

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A solid nonconducting sphere of radius R has a charge Q uniformly distributed throughout its volume. A Gaussian surface of radiu
anyanavicka [17]

Answer:

1. E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

Explanation:

According to the problem, Q is the charge on the non conducting sphere of radius R. Let ρ be the volume charge density of the non conducting sphere.

As shown in the figure, let r be the radius of the sphere inside the bigger non conducting sphere. Hence, the charge on the sphere of radius r is :

Q₁ = ∫ ρ dV

Here dV is the volume element of sphere of radius r.

Q₁ = ρ x 4π x ∫ r² dr

The limit of integration is from 0 to r as r is less than R.

Q₁ = (4π x ρ x r³ )/3

But volume charge density, ρ = \frac{3Q}{4\pi R^{3} }

So, Q_{1} = \frac{Qr^{3} }{R^{3} }

Applying Gauss law of electrostatics ;

∫ E ds = Q₁/ε₀

Here E is electric field inside the sphere and ds is surface element of sphere of radius r.

Substitute the value of Q₁ in the above equation. Hence,

E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

7 0
4 years ago
A man pushes a shopping cart across a level floor. What force resists the effort force? A) gravity B) friction C) the normal for
Kipish [7]

Answer:

B) Friction

Explanation:

Friction is a force that acts when an object is sliding along a surface. Microscopically, this force is due to the fact that the two surfaces are not perfectly smooth, but they have "imperfections" that cause a force that opposes the motion of the object.

For an object sliding on a flat surface, the force of friction has magnitude:

F_f = \mu_k mg

where

\mu_k is the coefficient of kinetic friction

m is the mass of the object

g is the acceleration of gravity

The direction of the force of friction is always opposite to the direction of motion of the object.

In reality, friction also acts if the object is at rest and it is pushed by a force; in this case, we talk about static friction, and its magnitude is

F_f = \mu_s mg

where \mu_s is called coefficient of static friction, and it is generally larger than the coefficient of kinetic friction.

8 0
3 years ago
Which one of the following substances is a liquid fuel used in rocket engines?
melomori [17]

There are none on the list you included with your question.

8 0
4 years ago
Read 2 more answers
Which term is used to describe the variety of inheritable traits in a species?
choli [55]
Genetic i think is it right?
7 0
3 years ago
Read 2 more answers
A firecracker in a coconut blows the coconut into three pieces. two pieces of equal mass fly off south and west, perpendicular t
netineya [11]
Here we have mass that moves at ceratin speed. This means that we have momentum. The law that must be observed is law of conservation of momentum. It states that momentum before certain event is equal to a momentum after that event. Here we have three masses so we can write this as:
m_{1}  v_{1i} + m_{2}  v_{2i} + m_{3}  v_{3i} = m_{1}  v_{1f} + m_{2}  v_{2f} + m_{3}  v_{3f}
Before the firecracker blows a coconut does not move, so left side is equal to 0:
0 = m_{1} v_{1f} + m_{2} v_{2f} + m_{3} v_{3f}

We know that m1=m2=m and m3=2m. Also we are asked to find v3f so we can rewrite formula:
v_{3f} = -  \frac{m_{1}  v_{1f}  + m_{2} v_{2f} }{ m_{3} }

We must take in consideration that two parts with same mass do not move in same direction. The center of mass of these two parts moves between them at angle of 45° with respect to both south and west. The speed of a center of mass is:
v_{f} = \sqrt{ v_{1f}^{2}+ v_{2f}^{2} } \\ \\ v_{f} = 33.9m/s
This speed we can insert into formula for v3f:
v_{3f} = - \frac{m*33.9+m*33.9 }{ 2m } \\  \\ v_{3f} = - \frac{2m*33.9 }{ 2m }  \\  \\ v_{3f} = - 33.9m/s

We can see that part of a coconut with biggest mass has same speed as center of mass of two other parts. Negative sign shows that direction is opposite to direction of two pats. Biggest part moves towards north-east.
8 0
3 years ago
Read 2 more answers
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