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motikmotik
3 years ago
14

One end of the rope is vibrated to produce a wave with a wavelength of .25 m. The Frequency

Physics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

Wave speed = 1.25 m/s

Explanation:

Given that the

wavelength = 0.25 m.

Frequency F = 5.0 Hz

The speed of a wave is the product of wave frequency and the wavelength. That is

V = F λ

Where

V = wave speed (m/s)

λ = wavelength (m).

F = frequency (Hz).

Using the formula above gives:

V = 0.25 × 5

V = 1.25 m/s

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If you start with a substance as a solid, what will happen to the molecules as you add thermal energy (heat)?
AveGali [126]

Answer:

C. molecules speed up as more thermal energy is added

Explanation:

The molecules will simply speed up as more thermal energy is added to the solid.

Thermal energy is a form of kinetic energy which is set in motion.

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  • As the molecules of the solid gains heat, they will continue to increase in thermal energy.
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4 years ago
What effect does temperature have on the composition of ocean water?
Burka [1]
The answer is letter B. XD
4 0
4 years ago
Read 2 more answers
Kon'nichiwa~<br>please help me with this question!!​
andrezito [222]

Let's check the relationship

\\ \rm\hookrightarrow g=\dfrac{GM}{r^2}

\\ \rm\hookrightarrow g\propto G

So

  • Raindrops will fall faster . .
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Option C is wrong by now .Let's check D once

\\ \rm\hookrightarrow T\propto \dfrac{1}{\sqrt{g}}

  • So time period of simple pendulum would decrease.

4 0
2 years ago
A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m.
KengaRu [80]

Potential energy = (weight) x (height)

After the car has been raised 2.5 meters, it has

                 (11,000) x (2.5) = 27,500 Joules

MORE potential energy than it had before it was lifted.

That's the energy that has to come from the work you do to lift it.

Since no mechanical process is ever 100% efficient, the work required
to accomplish this task is <em>at least  27,500 joules</em>.


5 0
3 years ago
Read 2 more answers
I just need number 2
il63 [147K]

We will apply the conservation of linear momentum to answer this question.

Whenever there is an interaction between any number of objects, the total momentum before is the same as the total momentum after. For simplicity's sake we mostly use this equation to keep track of the momenta of two objects before and after a collision:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

Note that v₁ and v₁' is the velocity of m₁ before and after the collision.

Let's choose m₁ and v₁ to represent the bullet's mass and velocity.

m₂ and v₂ represents the wood block's mass and velocity.

The bullet and wood will stick together after the collision, so their final velocities will be the same. v₁' = v₂'. We can simplify the equation by replacing these terms with a single term v'

m₁v₁ + m₂v₂ = m₁v' + m₂v'

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Let's assume the wood block is initially at rest, so v₂ is 0. We can use this to further simplify the equation.

m₁v₁ = (m₁+m₂)v'

Here are the given values:

m₁ = 0.005kg

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m₂ = 5kg

Plug in the values and solve for v'

0.005×500 = (0.005+5)v'

v' = 0.4995m/s

v' ≅ 0.5m/s

4 0
3 years ago
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