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2 years ago

Which best explains how the diffraction pattern observed in young’s experiment supports the wave theory of light?.

Physics

1 answer:

KIM [24]2 years ago

6 0

Answer: the airy pattern can only arise from wave propagation

Explanation:if particles went in straight lines through a slit, they would progate linearly and not interfere. The airy pattern arises from diffraction as waves interfere, producing peaks (constructive interference where peaks of waves from each slit coincide) and troughs (destructive interference where peaks and troughs of waves from each slit cancel out). If intensity rather than field is measured nodes occur where 0 values line up instead of troughs

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A car moved 35 km to the South and Then 10 km to the North. What is its Displacement?

Harrizon [31]

Answer:

It's displacement would be 25 km.

Explanation:

That is because you would subtract 10 from 35 to get the distance away from the starting point.

3 0

2 years ago

Which statement correctly describes these electric field lines?

Otrada [13]

I don’t know, which statement ahh I see white screen lol

4 0

3 years ago

19. A 0.0340 kg bullet traveling at 120 m/s embeds itself in a 1.24 kg wooden block which

Blababa [14]

Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

3 0

3 years ago

What are the answers is a quiz

defon

Answer:19

Explanation:

4 0

3 years ago

A spectral line from a star is observed to have a wavelength of 656.5 nm. The rest wavelength of this line is 656.8 nm. (a) What

nignag [31]

Answer:

speed of star is 1.37 × $10^{5}$ m/s

it is approaching to earth because wavelength of star is decreasing than rest

if emit same wavelength it does not move anywhere

it will remain steady condition with respect earth

Explanation:

given data

wavelength = 656.5 nm

rest wavelength = 656.8 nm

to find out

the speed of the star , is it approaching

solution

we know here equation that is

wavelength shift / wavelength at rest = velocity of source / speed of light

so put all value and find

velocity of source = 3 × $10^{-9}$ × 3 × $10^{8}$ / 656.8 × $10^{-9}$

velocity of source star = 1.37 × $10^{5}$ m/s

and

it is approaching to earth because wavelength of star is decreasing than rest

and

if emit same wavelength it does not move anywhere

it will remain steady condition with respect earth

6 0

3 years ago