humidity can be measured by the simplest hygrometer, called a sling psychrometer. It is composed of two thermometers placed together with a handle set to a chain. One of the thermometers is just like any other thermometer. Erstwhile the other one has a cloth wick wrapped over its bulb and is called a wet-bulb thermometer.
Have a great day!
-Pepetreefrogthe2nd
Answer:
Mass = 20,000 g
Explanation:
Given data:
Mass of MgO formed = ?
Mass of Mg react = 12 Kg (12 Kg × 1000/1 Kg = 12000 g)
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 12000 g/ 24 g/mol
Number of moles = 500 mol
Now we will compare the moles of Mg and MgO.
Mg : MgO
2 : 2
500 : 500
Mass of MgO:
Mass = number of moles × molar mass
Mass = 500 mol × 40 g/mol
Mass = 20,000 g
"Decaying swamps are covered with seawater" step ONLY occurs in the formation of coal.
<u>Option:</u> B
<u>Explanation:</u>
Coal production continues in regions of swampy wetlands because groundwater is near to or just above the topsoil. Because of this, organic matter is created quickly by the flora present-faster even than it can be broken down. Layers of organic matter are deposited in these areas, and then buried.
Based on the plants and circumstances present, the mechanism that produces coal varies somewhat in various areas but the ultimate method is similar. Coal production has two primary phases: peatification, and coalification. It is a solid black, readily combustible fossil fuel containing a large quantity of carbon-based material-about 50 percent of its mass.
Answer:
68.6 °C
Explanation:
From conservation of energy, the heat lost by acetone, Q = heat gained by aluminum, Q'
Q = Q'
Q = mL where Q = latent heat of vaporization of acetone, m = mass of acetone = 3.33 g and L = specific latent heat of vaporization of acetone = 518 J/g
Q' = m'c(θ₂ - θ₁) where m' = mass of aluminum = 44.0 g, c = specific heat capacity of aluminum = 0.9 J/g°C, θ₁ = initial temperature of aluminum = 25°C and θ₂ = final temperature of aluminum = unknown
So, mL = m'c(θ₂ - θ₁)
θ₂ - θ₁ = mL/m'c
θ₂ = mL/m'c + θ₁
substituting the values of the variables into the equation, we have
θ₂ = 3.33 g × 518 J/g/(44.0 g × 0.9 J/g°C) + 25 °C
θ₂ = 1724.94 J/(39.6 J/°C) + 25 °C
θ₂ = 43.56 °C + 25 °C
θ₂ = 68.56 °C
θ₂ ≅ 68.6 °C
So, the final temperature (in °C) of the metal block is 68.6 °C.
