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ziro4ka [17]
3 years ago
8

Which type of bond is where two atoms are sharing one or more valence electrons?

Chemistry
1 answer:
a_sh-v [17]3 years ago
6 0
The answer is covalent bond!
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S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?
Brilliant_brown [7]

Answer:  There are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)

Here, 1 mole of S is reaction with 3 moles of F_{2} which means 1 mole of S requires 3 moles of F_{2}.

Therefore, moles of F_{2} required to react completely with 2.30 moles S are calculated as follows.

1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}

Thus, we can conclude that there are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

3 0
3 years ago
Which scenario best describes a relationship of parasitsm
saveliy_v [14]
Parasitism... basically a tick and a dog. The dog is the host, which is harmed by the tick.
3 0
3 years ago
Help science periodic table
romanna [79]
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps

3 0
3 years ago
Read 2 more answers
Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1
lina2011 [118]

Answer : The correct option is, (B) 273.15 K and 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

STP conditions :

The temperature is, 0^oC or 273.15K or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is 22.4 L for 1 mole of a substance.

Hence, the correct option is, (B) 273.15 K and 1 atm

7 0
3 years ago
The following reaction is at equilibrium in a sealed container.
ale4655 [162]

Answer:

D.Lowering the temperature is the best option.

Explanation:

The value of equilibrium constants aren't changed with change in the pressure or concentrations of reactants and products in equilibrium. The only thing that changes the value of equilibrium constant is a change of temperature.

In the reaction below for example;

A + B <==>C+D

If you have moved the position of the equilibrium to the right (and so increased the amount of C and D), why hasn't the equilibrium constant increased?

Let's assume that the equilibrium constant mustn't change if you decrease the concentration of C - because equilibrium constants are constant at constant temperature. Why does the position of equilibrium move as it does?

If you decrease the concentration or pressure of C, the top of the Kc expression gets smaller. That would change the value of Kc. In order for that not to happen, the concentrations of C and D will have to increase again, and those of A and B must decrease. That happens until a new balance is reached when the value of the equilibrium constant expression reverts to what it was before.

3 0
3 years ago
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