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Elodia [21]
2 years ago
7

Calculate the mass (g) of each product formed when 43.82 g of diborane (B₂H₆)

Chemistry
1 answer:
guajiro [1.7K]2 years ago
6 0

Stoichiometry:

The area of study in chemistry concerned with the quantities of chemical species produced or required for a given chemical reaction is stoichiometry. The stoichiometric coefficients of the balanced chemical equation are often used to relate the amounts of substances to one another.

Evaluation :

The balanced chemical equation for the reaction is given as follows:

B_{2} H_{6} + 6H_{2} O  → 2H_{3} BO_{3}  + 3H_{2}

By using the molar mass of the given chemical species, along with the stoichiometric coefficients of the balanced chemical equation, we determine the mass of each product as:

43.82 g B_{2} H_{6} ×\frac{1 Mol B_{2} H_{6} }{27.66 g} ×\frac{3molH_{2} }{1 molB_{2}H_{6}  } ×\frac{2g}{1 mol H_{2} } = 9.51 g H_{2}

43.82 g B_{2} H_{6} × \frac{1 mol B_{2} H_{6} }{27.66 g}    ×   \frac{1 mol H_{3}BO_{3}  }{1 mol B_{2} H_{6} } × \frac{61.8g}{1 mol H_{3} BO_{3} }  = 196 gH_{3} BO_{3}

Learn more about chemical reaction :

brainly.com/question/1893305

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3 years ago
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How will the price of a product impact on the profits of the entrepreneur​
taurus [48]

Answer:

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Explanation:

3 0
3 years ago
What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?
notsponge [240]
The  empirical formula  for a compound   is KClO3

     Explanation 
 
find  the  moles of each  element
moles  = % composition/molar  mass

molar  mass of  of  potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles  of potassium  =  31.9 / 39 = 0.818  moles
moles of  chlorine    = 28.9/35.5 = 0.814 moles
moles of   oxygen  =  39.2/  16 =  2.45  moles


find the  mole ratio  by  dividing   with  the smallest  mole = 0.814  moles

potassium = 0.818/0.814  =1  
chlorine  =  0.814/0.814 = 1
oxygen =  2.45 /0.814 =3 


the empirical  formula   is therefore = KClO3
7 0
3 years ago
How to do 22.4 kg/L to kg/mL
emmainna [20.7K]
1 kg/L ----------- 0.001 kg/mL
22.4 kg/L ------- ??

22.4 x 0.001 / 1 => 0.0224 kg/mL
6 0
3 years ago
The PH of a solution of Hcl is 2.find out the amount of acid present in a litre of the solution ​
Scrat [10]

Answer:

The solution is 10^-2 or 0.01M in HCl.

Explanation:

meaning of pH is "power of hydrogen".

what is the molar concentration of a HCl solution with pH=2?

Let say pH=2

[H+]=10^-2M

HCL is a strong acid that dissociates completely:

[H+]=[HCL]

Therefore solution is 10^-2 or 0.01M in HCL.

5 0
3 years ago
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