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Elodia [21]
2 years ago
7

Calculate the mass (g) of each product formed when 43.82 g of diborane (B₂H₆)

Chemistry
1 answer:
guajiro [1.7K]2 years ago
6 0

Stoichiometry:

The area of study in chemistry concerned with the quantities of chemical species produced or required for a given chemical reaction is stoichiometry. The stoichiometric coefficients of the balanced chemical equation are often used to relate the amounts of substances to one another.

Evaluation :

The balanced chemical equation for the reaction is given as follows:

B_{2} H_{6} + 6H_{2} O  → 2H_{3} BO_{3}  + 3H_{2}

By using the molar mass of the given chemical species, along with the stoichiometric coefficients of the balanced chemical equation, we determine the mass of each product as:

43.82 g B_{2} H_{6} ×\frac{1 Mol B_{2} H_{6} }{27.66 g} ×\frac{3molH_{2} }{1 molB_{2}H_{6}  } ×\frac{2g}{1 mol H_{2} } = 9.51 g H_{2}

43.82 g B_{2} H_{6} × \frac{1 mol B_{2} H_{6} }{27.66 g}    ×   \frac{1 mol H_{3}BO_{3}  }{1 mol B_{2} H_{6} } × \frac{61.8g}{1 mol H_{3} BO_{3} }  = 196 gH_{3} BO_{3}

Learn more about chemical reaction :

brainly.com/question/1893305

#SPJ4

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Answer:

Mole fraction of CH_4O = 0.58

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Explanation:

Let the mass of CH_4O and C_2H_6O = x g

Molar mass of CH_4O = 33.035 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

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Mole fraction of C_2H_6O = 1 - 0.58 = 0.42

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