<span>The question is 'a centre seeking force related to acceleration is ............... force. The answer is centripetal force. Motion in a curved path is an accelerated motion and it requires a force that will direct the moving object towards the centre of curvature of the path of motion. This centre seeking force is known as centripetal force.</span>
Answer:
(a) 4.27 x 10^-4 Telsa
(b) 3.28 x 10^-4 Telsa
Explanation:
side of square, a = 5.49 cm
inner radius, r = 18.1 cm = 0.181 m
number of turns,N = 450
current, i = 0.859 A
(a)
The magnetic field due to a solenoid due to inner radius is


B = 4.27 x 10^-4 Telsa
(b)
The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m
The magnetic field due to the outer radius is


B = 3.28 x 10^-4 Tesla
Answer:
- 1.07 ft
Explanation:
V1 = (-5, 7, 2)
V2 = (3, 1, 2)
Projection of v1 along v2, we use the following formula
=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}
So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4
The magnitude of vector V2 is given by
= 
So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft
Thus, the projection of V1 along V2 is - 1.07 ft.
so we need to find the direction of v2