A3 kg mass takes some impulse in order increase its velocity from 11
1 answer:
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Answer:
.
Explanation:
The efficiency of a machine is the ratio between the useful output and the energy input:
Rearrange this equation to find energy input in terms of efficiency and useful output:
.
Substitute in the values: and
. Evaluate to find the value of
:
.
(Rounded to two significant figures as in the value of efficiency.)
Answer:
vi = 2.83 √gR
Explanation:
For this exercise we can use the law of conservation of energy
Let's take a reference system that is at point A, the lowest
Starting point. Lower, point A
Em₀ = Ki = ½ m vi²
Final point. Higher, point B
= K + U
It indicates that at this point the kinetic energy is ki / 2 and the potential energy is ki / 2
K = ki / 2
U = m g (2R)
Energy is conserved so
Em₀ = Em_{f}
½ m vi² = ½ (1/2 m vi²) + m g 2R
½ m vi² (1- ½) = m g 2R
vi² = 4 g 2 R
vi = √ 8gR = 2 √2gR
vi = 2.83 √gR
Answer:
A large piece of charcoal on a grill in the sunlight (if it's burning) will consist of the following types of energy:
- Chemical
- Heat and
- Light
Explanation:
Charcoal is basically carbon which is produced when wood is heated strongly in the absence of oxygen. From a chemistry point of view, charcoal contains combustible carbon whose chemical formula is C. Sometimes, which is water may be found in it but in very small units.
All matter contains Heat energy. Charcoal is not an exception. As the charcoal burns, the heat energy is produced along with Light energy.
Light comes in many forms such as Infrared rays, Xrays, Visible Spectrum light, etc.
The glow which the coal gives off fall under the visible spectrum of light.
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