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3 years ago

How can a wave carry information?

2 answers:

7 0

A transmitter “encodes” or modulates messages by varying the amplitude or frequency of the wave – a bit like Morse code. At the other, a receiver tuned to the same wavelength picks up the signal and 'decodes' it back to the desired form

I think it’s A or D

Katen [24]3 years ago

4 0

Answer:

i think its A

Explanation:

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Which statement about electromagnetic waves is true?

zhuklara [117]

Electromagnetic waves don't require a medium to travel.

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3 years ago

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For the chemical reaction C2H6 --> C2H4 + H2 + 137kJ, the chemical energy of the A. reactant and the chemical energy of the p

Goryan [66]

Answer: The chemical energy of reactants is greater than the chemical energy of products.

Explanation: In the given reaction

$C_2H_6\rightarrow C_2H_4 + H_2 +137 kJ$

It can be seen that the energy has been released. Thus we can say that reactants have converted to products by release of energy. Thus energy of products is less as compared to energy of reactants as some of the energy has been released.

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3 years ago

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If the earth were twice the distance from the sun that it is now, the gravitational force exerted on it by the sun would be: a)

devlian [24]

Answer:

a) 1/4 what it is now

Explanation:

As we know that force of gravitation between two planets at some distance "r" from each other is given as

$F_g = \frac{Gm_1m_2}{r^2}$

now since we know that if the distance between Earth and Sun is changed

So the force of gravity will be given as

$\frac{F_g'}{F_g} = \frac{r_1^2}{r_2^2}$

now we know that the distance between sun and earth is changed to twice the initial distance between them

so we have

$r_2 = 2r_1$

so new gravitational force between sun and earth is given as

$F_g' = \frac{r_1^2}{(2r_1)^2}F_g$

$F_g' = \frac{1}{4}F_g$

4 0

4 years ago

Biological factor related to antisocial personality disorder is

dusya [7]

Schizotypal personality disorder and borderline personality disorder

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3 years ago

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In a race, a runner traveled 12 meters in 4.0 seconds as she accelerated uniformly from rest. The magnitude of the acceleration

mestny [16]

The runner is moving by uniformly accelerated motion, starting from rest (so, his initial velocity is zero). The law of motion of the runner is
 $x(t) = \frac{1}{2} at^2$ 
where x(t) is the distance covered after time t, and a is the acceleration of the runner. By re-arranging the formula, we get
 $a= \frac{2S}{t^2}$ 
We know the runner has covered a distance of S=12m in t=4.0 s, and if we plug these numbers into the equation, we find the acceleration of the runner:
 $a= \frac{2S}{t^2} = \frac{(2*12m)}{(4s)^2} =1.5 m/s^2$

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3 years ago