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barxatty [35]
3 years ago
6

What is saponification​

Chemistry
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

Saponification is a process that involves the conversion of fat, oil, or lipid, into soap and alcohol by the action of heat in the presence of aqueous alkali. Soaps are salts of fatty acids and fatty acids are monomers of lipids that have long carbon chains e.g. sodium palmitate.

Explanation:

I hope it's help u :)

kirill [66]3 years ago
6 0
I dont know BUT here’s a puppy

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Need help ASAP!! Full paragraph! Will give Brainliest!!
Amanda [17]

Answer:

All elements in the same group of the periodic table have the same number of valence electrons. This made it possible to compare the valence of the alien elements to the valence of elements from our periodic table, and match the alien elements to the correct group. For example, our group 14 elements all have 4 valence electrons, so the alien element with 4 valence electrons had to be part of group 14 also.

8 0
3 years ago
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Mutations that neither benefit nor harm the organism have (blank) effect on the organisms survival
Daniel [21]

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

Explanation:

3 0
3 years ago
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Which of the following are considered pure substances?
Helen [10]
B.Elements

Explanation: they cannot be separated
8 0
3 years ago
A waste collection tank can hold 18,754 kg of methanol, which has a density of 0.788 g/cm3. What is the volume of the waste coll
Ivahew [28]
A is correct hope this helps
4 0
3 years ago
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What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

8 0
3 years ago
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