Answer:
Honestly I cant understand that so please explain it someone
Explanation:
Explanation:
The given data is as follows.
radius (r) = 3.25 cm, 
Now, we will calculate the tangential acceleration as follows.

Putting the given values into the above formula as follows.

= 
= 37.7 
Thus, we can conclude that the tangential acceleration of a point on the rim of the flywheel during this spin-up process is 37.7
.
Answer:
a) x_{cm} = m₂/ (m₁ + m₂) d
, b) x_{cm} = 52.97 pm
Explanation:
The expression for the center of mass is
= 1 / M ∑
Where M is the total masses, mI and xi are the mass and position of each element of the system.
Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon
x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)
Let's reduce the magnitudes to the SI system
m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg
m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg
d = 128 pm = 128 10⁻¹² m
The equation for the center of mass is
x_{cm} = m₂/ (m₁ + m₂) d
b) let's calculate the value
x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12
x_{cm} = 52.97 10⁻¹² m
x_{cm} = 52.97 pm
Answer:
(D) F/2
Explanation:
Since the circular section is unbanked, the centripedal acceleration acting on each of the cars is


Therefore the centripetal force on each car


Since
this means the friction force required to keep the large car on the road is only half of the friction force required to keep the small car on road
So (D) F/2 is the correct answer