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3 years ago

8a.The mass of a girl is 40 kg. Calculate her weight. (g = 9.8 m/s)

Physics

2 answers:

Archy [21]3 years ago

8 0

Answer:

The right answer of 8 a is 392 Newton

The right answer of 8b is 10 kg

Look at the attached picture

Hope it will help you

Good luck on your assignment

yaroslaw [1]3 years ago

3 0

Explanation:

Here,

Given,

Mass(m)=40 kg

Gram=9.8m/s

Now,

Weight=m x g

or, weight= 40x9.8

=392.0

Hope you have understood

Mark me as brainliest plz

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2 years ago

A gyroscope flywheel of radius 3.25 cm is accelerated from rest at 11.6 rad/s2 until its angular speed is 1820 rev/min. (a) What

kati45 [8]

Explanation:

The given data is as follows.

radius (r) = 3.25 cm, $\alpha = 11.6 rad/s^{2}$

Now, we will calculate the tangential acceleration as follows.

$a_{tangential} = \alpha \times r$

Putting the given values into the above formula as follows.

$a_{tangential} = \alpha \times r$

= $11.6 rad/s^{2} \times 3.25 cm$

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3 years ago

A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist

kvasek [131]

Answer:

a) x_{cm} = m₂/ (m₁ + m₂) d , b) x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

$x_{cm}$ = 1 / M ∑ $x_{i}$ $m_{i}$

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

x_{cm} = m₂/ (m₁ + m₂) d

b) let's calculate the value

x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12

x_{cm} = 52.97 10⁻¹² m

x_{cm} = 52.97 pm

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2 years ago

8. Express 2.69 x 10^9 in standard form.

taurus [48]

Answer:

242.1

Explanation:

10 x 9 equals 90

2.69 x 90 = 242.1

5 0

2 years ago

A small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbank

Alenkasestr [34]

Answer:

(D) F/2

Explanation:

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$a_s = \frac{v_s^2}{r} = \frac{(2v)^2}{r} = \frac{4v^2}{r}$

$a_l = \frac{v_l^2}{r} = \frac{v^2}{r}$

Therefore the centripetal force on each car

$F_s = m_sa_s = \frac{4mv^2}{r}$

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So (D) F/2 is the correct answer

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3 years ago