Answer:
HCP
Extra -> BCC the most, FCC between
Explanation:
Answer:a
Explanation:
Given
![[H^+]=5.3\times 10^{-4}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D5.3%5Ctimes%2010%5E%7B-4%7D%5C%20M)
and 
Also ![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
therefore 
Thus 
and ![pOH=-\log [OH^{-}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E%7B-%7D%5D)
![[OH]^{-1}=10^{-10.25}](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D10%5E%7B-10.25%7D)
![[OH]^{-1}=1.88\times 10^{-11}\ M](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D1.88%5Ctimes%2010%5E%7B-11%7D%5C%20M)
As the pH is less than 7 therefore solution is acidic
Since the rocket’s acceleration is 3.00 m/s^3 * t, its acceleration is increasing at the rate of 3 m/s^3 each second. The equation for its velocity at a specific time is the integral of the acceleration equation.
<span>vf = vi + 1.5 * t^2, vi = 0 </span>
<span>vf = 1.5 * 10^2 = 150 m/s </span>
This is the rocket’s velocity at 10 seconds. The equation for its height at specific time is the integral velocity equation
<span>yf = yi + 0.5 * t^3, yi = 0 </span>
<span>yf = 0.5 * 10^3 = 500 meters </span>
<span>This is the rocket’s height at 10 seconds. </span>
<span>Part B </span>
<span>What is the speed of the rocket when it is 345 m above the surface of the earth? </span>
<span>Express your answer with the appropriate units. </span>
<span>Use the equation above to determine the time. </span>
<span>345 = 0.5 * t^3 </span>
<span>t^3 = 690 </span>
<span>t = 690^⅓ </span>
<span>This is approximately 8.837 seconds. Use the following equation to determine the velocity at this time. </span>
<span>v = 1.5 * t^2 = 1.5 * (690^⅓)^2 </span>
<span>This is approximately 117 m/s. </span>
<span>The graph of height versus time is the graph of a cubic function. The graph of velocity is a parabola. The graph of acceleration versus time is line. The slope of the line is the coefficient of t. This is a very different type of problem. For the acceleration to increase, the force must be increasing. To see what this feels like slowly push the accelerator pedal of a car to the floor. Just don’t do this so long that your car is speeding!!</span>
Answer:
paper burned and turned into smoke...
Explanation:
When a chemical reaction has taken place that means that whatever the starting variable is, (in this case it was the paper) then it cannot go back to its original state... you can also tell if a chemical reaction has taken place if the test releases any kind of gas, if there is a temperature change, or if there is a color change. Which this time it changed from paper into smoke which is a gas
Hope This Helps
