Answer:
14 moles of CO are needed in the reaction, to react with 7 moles of O₂
Explanation:
We need to determine the reaction to start:
O₂ (g) + 2CO (g) → 2CO₂ (g)
Now, we state the ratio of reactants:
1 mol of oxygen needs 2 moles of CO, to react and they both, produce 2 moles of CO₂. Therefore the ratio is 1:2
We can make a rule of three to reach the answer:
1 mol of O₂ needs 2 moles of CO to react
Therefore, 7 moles of O₂ must need (7 .2) /1 = 14 moles
Answer: D) helium.
Explanation:
Nuclear fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

Nuclear fusion is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.
Example: 
Thus when deuterium and tritium , the two isotopes of hydrogen are fused, a heavier nuclei helium is being formed from two smaller nuclei releasing a neutron.
Answer:
d = 0.743 g/cm³
Explanation:
Given data:
Mass of cylinder = 65.34 g
Height = 15.60 cm
Radius = 1.34 cm
Density of cylinder = ?
Solution:
Volume of cylinder:
V = πr²h (π = 22/7)
V = 88 cm³
Density of cylinder:
d = m/v
d = 65.34 g / 88 cm³
d = 0.743 g/cm³
Answer:
The volume is 583.02 mL
Explanation:
Given that the density is:-
The mass,
The expression for the calculation of density is shown below as:-
Using the above expression to calculate the volume as:-
Applying the values to calculate the volume as:-
<u>The volume is 583.02 mL.</u>
Answer:
4.87g
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of solution = 0.35kg
Molality = 0.238 m
Mass of NaCl =..?
Step 2:
Determination of the number of mole of NaCl in the solution.
Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:
Molality = mol of solute /mass of solvent (kg)
With the above formula, we calculate the mole of NaCl present in the solution as follow:
Molality = mol of solute /mass of solvent (kg)
0.238 = mol of NaCl /0.35
Cross multiply
mol of NaCl = 0.238 x 0.35
mol of NaCl = 0.0833 mol
Step 3:
Determination of the mass of NaCl in 0.0833 mol of NaCl.
This is illustrated below:
Number of mole NaCl = 0.0833 mol
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl =..?
Mass = number of mole x molar Mass
Mass of NaCl = 0.0833 x 58.5
Mass of NaCl = 4.87g
Therefore, 4.87g of NaCl is contained in the solution.