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Romashka [77]
4 years ago
10

Petroleum is used to make synthetic plastics and numerous petrochemicals. True or false

Chemistry
1 answer:
nadya68 [22]4 years ago
3 0
True, Petroleum is used to make synthetic plastics and numerous petrochemical.
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Which of the following set ups which converts centimeters to fit
Eva8 [605]

Answer:

The fourth one down

Explanation:

It is the only setup in which the units of "cm" and "in" cancel correctly and give the desired units of "ft."

The second one down has the correct units but the wrong conversion factor for converting centimetres to inches.

5 0
3 years ago
The science of using tree rings to determine absolute age is called
leva [86]
Option c. dendrochronology

tree rings or dendrochronology they allow to use it in calibration for carbon-14 on temporal placements of fragments of wood (from long dead trees).

Example Bristle cone pines (1957) 4723 years old
4 0
4 years ago
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Which of the following choices represents a balanced chemical equation? A. Ca3(PO4)2 + 6SiO2 → P4O10 + 3CaSiO3 B. 2Ca3(PO4)2 + 6
Arturiano [62]

 the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

6 0
3 years ago
You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
3 years ago
Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = \frac{15.0 g}{40 g/mol}=0.375 mol

Molarity of the nitric acid solution = 0.250 M

Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

Molarity=\frac{Moles}{Volume(L)}

n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

\frac{1}{1}\times 0.0375 mol of NaOH

Moles of NaOH left unreacted  in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

1\times 0.3375 moles=0.3375 mol of hydroxide ion

The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

3 0
3 years ago
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