Answer:
Farmers who use conventional tillage use compost more than other farmers.
Explanation:
Convectional tillage is good to the environment because it attains the following;
- It increases porosity of the soil
- It loosens the soil thus allowing proper root growth and air exchange
- It is an effective way to incorporate manure and break sod fields
- Tilled soils warm faster in spring
Answer: (D: Tweezers)
A basic first aid kit is always good to have in case of an emergency. The typical items found in a first aid kit are pain reliever, tweezers, alcohol wipes, gloves, antiseptic, medical tape, sterile gauze, insect bite swaps, triple-antibiotic ointment, hydrogen peroxide, bandage scissors, instant cold compresses, and of course bandages. There are various types of bandages that can be included; elastic bandages, adhesive bandages, and triangular bandages for starters.
Explanation:
Answer:
A stack is an ordered list of elements where all insertions and deletions are made at the same end, whereas a queue is exactly the opposite of a stack.
Explanation:
Answer:
The radius of a wind turbine is 691.1 ft
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m
Explanation:
Given;
power generation potential (PGP) = 1000 kW
Wind speed = 5 mph = 2.2352 m/s
Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³
Radius of the wind turbine r = ?
Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²
Wind energy per unit mass of air = 2.517 J/kg
PGP = mass flow rate * energy per unit mass
PGP = ρ*A*V*e
r = 210.64 m = 691.1 ft
Thus, the radius of a wind turbine is 691.1 ft
PGP = CVᵃ
For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)
Let C = 0.4
PGP = Cvᵃ
take log of both sides
ln(PGP) = a*ln(CV)
a = ln(PGP)/ln(CV)
a = ln(1000)/ln(0.4 *2.2352) = 7.73
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m
Answer:
It will be B
Explanation:
Since resisitors in series are added together, 1 + 1 + 1 would = 3kilo ohms. But with resistors in parallel would be (1/1+1/1)^-1. That would equal 0.5 Now you have two resistors in series for B, and because now that they are in series you add them together, so 0.5 + 1 = 1.5 kilo ohms which is what is needed.
