Hi!
Two negatives make a positive, so this can be rewritten as
-7+2.5
The answer is D. -7+2.5
Hope this helps! :)
-Peredhel
Given:
The faces on a number cube are labeled 1,2,2,3,4, and 5.
The number cube is rolled 114 times.
To find:
How many times would you expect the number 2 to appear?
Solution:
We have,
Total outcomes = 1,2,2,3,4, and 5.
Number of total outcomes = 6
Favorable outcomes = 2 and 2
Number of favorable outcomes = 2
The probability of getting 2 is:
Now, the expected number of times when 2 to appear is:
Therefore, the expected number of times is 38.
Answer: 105
Step-by-step explanation: 25 frames is 1 second. The video already played 3 and 2/5 seconds before the player started to count 0, so you can write 3 and 2/5 seconds as an improper fraction. =(5*3)+2 / 5 = 17/5 seconds. Multiply by 25 frame. 17/5 *25 =85 frames. So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames. then to get the number of frames that were already in count you would subtract 85 frames from the 190 frames.
190-85=105 frames
(Not 100% sure so apologies if I'm wrong)
Answer:
6523
Step-by-step explanation:
I'm assuming that the question is asking us to rearrange the numbers 5,3,2,6 to obtain the largest possible value that is odd.
In order for a number to have the largest value, the first digit of the number must he the largest possible value. In this case, we see that the largest value is 6, hence the number must begin with 6 i.e 6XXX
We can do the same for the next digit in the hundreds position by picking the largest possible remaining number. In this case, it is the number 5. So the number will look something like this: 65XX
We see that the only remaining numbers are 3 and 2.
Recall that for a number to be odd, the digit on the ones place must also be odd. Of the remaining numbers, only 3 is odd, hence the last number must be 3. i.e 65X3
Hence the last remaining number is 2
6523
