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Mumz [18]
3 years ago
6

A laser beam is incident on two slits with a separation of 0.215 mm, and a screen is placed 5.45 m from the slits. an interferen

ce pattern appears on the screen. if the angle from the center fringe to the first bright fringe to the side is 0.183°, what is the wavelength of the laser light?
Physics
1 answer:
vladimir1956 [14]3 years ago
4 0
Use: dsin(θ) = mλ  where d is slit separation, m is fringe order (1 here), and 
θ = 0.183
Now λ = dsin(θ) /m = (0.215e-3)(sin(0.183))/1 = 6.867e-7 or λ = 687.7nm  
(red laser)
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Can someone give me an example or explanation of calculating energy from voltage? Many thanks!
antoniya [11.8K]
Expression to calculate energy from voltage: E= V*Q where E= energy, V= voltage, and Q= charge

Additional help:
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[ V = I x R ] V (volts) = I (amps) x R (Ω)

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[ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

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I hope that helps to some extent-
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10. Someone takes 11 minutes to walk up a hill 120m high. His weight is 550N.
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Answer:

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Every object in the universe exerts a force on every other object. This force is called
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A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work d
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Answer: 50.7 J

Explanation:

Given

mass of lion is  m=2.6\ kg

The initial speed of the lion is v_1=5\ m/s

increased speed of lion is v_2=8\ m/s

Initially, its kinetic energy is K_1=\frac{1}{2}mv_1^2

Final kinetic energy k_2=\frac{1}{2}mv_2^2

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5 0
3 years ago
An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror
andrew-mc [135]

Answer:

Position = \frac{60}{7}\ cm behind the mirror

Nature = Virtual and Erect

Size = \frac{15}{7}\ cm : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

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We have to use mirror formula to find image distance.

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Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification = =\frac{h_{image}}{h_{object}}=-\frac{v}{u}=\frac{60}{7\times20}=\frac{3}{7}

Height of the object = 5 cm

Height of the image = 5\times\frac{3}{7}=\frac{15}{7}\ cm

Since the height of the image is positive and less than the size of object,it is erect and diminished.

4 0
4 years ago
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