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Serhud [2]
3 years ago
10

Consider the same 70kg/686N student on the surface on another planet from the table above: Jupiter. Tompared to the gravitationa

l force or weight on Earth. How would we expect the student's weight to change? Explain. A) Because the mass of Jupiter is about 300 times greater than Earth's we would expect the student's weight to be 205,800N. B) Both the mass and the diameter of Jupiter is greater than Earth's. Considering both, the student's Earth weight would be multiplied by 3, or 2058N. Because Jupiter is considered a gas giant, rather than a rocky solid planet, there is no gravity and we could not calculate the student's new weight. D) Because the distance to Jupiter is about 500 million km farther from the Sun than Earth, we can expect the weight of the student to be 686N/5 or 137.2N​
Physics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

Dont mind me

Explanation:

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tatuchka [14]

Answer:

true

Explanation:

for example assume you are setting in a moving bus and when someone see you from the ground you are in motion but for some who is with you in the bus you are not in motion.

6 0
3 years ago
A cylinder contains 250 L of hydrogen gas (H2) at 0.0^∘Cand a pressure of 10.0 atm. How much energy is required to raise the tem
Over [174]

Answer:

The amount of energy needed to raise the temperature of the cylinder by 25 °C is 23.3 KJ of heat.

Explanation:

The step by step calculation can be found in the attachment below. Thank you.

8 0
3 years ago
Explain why a roller coaster’s second hill cannot be taller than the first hill.
max2010maxim [7]
There will not be enough momentum from the first hill to cross another hill if he same or larger size because of the way potential energy and kinetic energy works it will not be able go as high as it could go on he fist hill.
4 0
3 years ago
Read 2 more answers
Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude
aivan3 [116]

Answer:

E=6.8Kv/m

Explanation:

From the question we are told that

Distance b/w plate d=10cm=>0.1m

P_1 Potential at 7.35 V=533v

Generally the equation for electric field at a distance is mathematically given as

E=\frac{v}{d}

E=\frac{533}{7.85*10^-^2}

E=6789.808917

E=6.8*10^3

E=6.8Kv/m

7 0
3 years ago
CALCULATE: find the velocity of a wave in a wave pool if it's wavelength is 3.2 m and its frequency is 0.60 Hz
vampirchik [111]
Number 2 ( 1.3m/s) good luck!
6 0
3 years ago
Read 2 more answers
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