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Serggg [28]
3 years ago
9

What is the average speed of a car that travels a distance of 10 km in 30 min?

Physics
1 answer:
Natali [406]3 years ago
4 0

Answer:

The average speed of a car is 20 km/h.

Explanation:

We have,

Distance covered by car is 10 km

Time taken by the car to cover that distance is 30 min. 30 min means 0.5 hours.

It is required to find the average speed of a car. It can be calculated using formula of average speed which is given by :

v=\dfrac{d}{t}\\\\v=\dfrac{10\ km}{0.5\ h}\\\\v=20\ km/h

So, the average speed of a car is 20 km/h.

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Which of the following characterizes a beta ray? Choose all that apply. is electromagnetic radiation is a product of natural rad
uranmaximum [27]

Explanation:

When a radioactive substance decays then the fast moving electrons emitted by it is known as beta ray. Basically, a number of beta particles are ejected by a beta ray.

Symbol of a beta particle is ^{0}_{-1}e. A beta ray is a natural decay of a radioactive element. As we know that opposite charges get attracted towards each other. So, a beta ray gets attracted towards a positively charged plate.

Therefore, we can conclude that following are the characterizes a beta ray:

  • a product of natural radioactive decay.
  • is attracted to the positively charged plate in an electric field.
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8 0
3 years ago
A 3,000-N force gives an object an acceleration of 15 m/s^2. The mass of the object is
Bingel [31]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

According to the second Newton's Law,

<em>✔ We have : F = m x a ⇔ m = F/a </em>

  • m = 3000/15
  • m = 200 kg

The mass of the object is therefore 200 kg.

7 0
3 years ago
Read 2 more answers
PLEASE HELP! I'LL GIVE BRAINLEST​
melisa1 [442]

Answer:

Weight = 8.162 Newton.

Explanation:

Given the following data;

Mass = 2.2 kg

Acceleration due to gravity = 3.71 N/kg

To find the weight of the textbook;

Weight = mass * acceleration due to gravity

Weight = 2.2 * 3.71

Weight = 8.162 N

Therefore, the weight of the science textbook in mars is 8.162 Newton.

3 0
3 years ago
a swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across the river that has a downstream cur
Doss [256]
Refer to the diagram shown below.

Still-water speed  = 9.5 m/s
River speed = 3.75 m/s down stream.

The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.

The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s

The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°

Answer:  10.2 m/s at 21.5° downstream.

7 0
3 years ago
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Which of the following best describes the location of the
marshall27 [118]

Answer:

The mantle exists above the crust of the earth

8 0
2 years ago
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