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andrey2020 [161]
3 years ago
9

The freezing point of a 0.30 m KCl solution will have the same freezing point that a 0.20 m Ca(NO3)2 solution.

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
6 0
False freezing point does not depend on volume
Tcecarenko [31]3 years ago
3 0
False it doesn’t depend on volume
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A silver cube with an edge length of 2.42 cm and a gold cube with an edge length of 2.75 cm are both heated to 85.4 ∘C and place
kakasveta [241]

Answer:

Explanation:

Volume of silver cube = 2.42³ = 14.17 cm³

mass of silver cube = volume x density

= 14.17 x 10.49 = 148.64 gm

Volume of gold cube = 2.75³ = 20.8  cm³

mass of gold cube =  20.8 x 19.3 = 401.44 gm

specific heat of silver and gold are .24 and .129 J /g°C

mass of 112 mL water = 112 g

Heat absorbed = heat lost = mass x specific heat x temperature fall or rise

Heat lost by metals

= 148.64 x .24 x ( 85.4 -T) + 401.44 x .129 x ( 85.4 - T )

= (35.67 + 51.78 ) x ( 85.4 - T )

87.45 x ( 85.4 - T )

= 7468.23 - 87.45 T

Heat gained by water

= 112 x 1 x ( T - 20.5 )

= 112 T - 2296

Heat lost = heat gained

7468.23 - 87.45 T = 112 T - 2296

199.45 T = 9764.23

T = 48.95° C

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3 years ago
An independent variable is what you___in an experiment. (There are no selections so please just answer it)
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A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.144g of Oxygen.calculate the percentage compos
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Answer:

Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%

<h2>Hope it's Helpful!!✌️</h2>
5 0
2 years ago
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