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3 years ago

Use this diagram to determine which of the following statements is true.

Chemistry

1 answer:

natima [27]3 years ago

3 0

Answer:

D. Catalysts speed up the rate of reactions by lowering the amount of energy required for the reaction to proceed.

Explanation:

A catalyst is a substance that:

speeds up the rate of a reaction .

does not alter the products of the reaction .

is unchanged chemically and in mass at the end of the reaction.

<em>A catalyst provides an alternative reaction pathway that has a lower activation energy than the uncatalyzed reaction. </em>

The figure shows how the energy of the reactants and products change during a reaction.

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I what process does a solid change directly into a vapor

Marina86 [1]

Answer:

solid change directly into a vapor in the process known simply as freezing

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3 years ago

How many molecules are in 2.00 moles of H20????????

Elis [28]

2x 6.022x10^23= 1.204x10^24

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3 years ago

When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2

MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is $\Delta \ T_f = T_{solvent}- T_{solution}$

$\Delta \ T_f = 2.9 ^0 \ C$

Using the depression in freezing point, the molar depression constant of the solvent $K_f = \dfrac{\Delta T_f}{m}$

$K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}$

$K_f = 4.82 ^0 C / m}$

The freezing point of the solution $\Delta T_f = T_{solvent} - T_{solution}$

$\Delta T_f = 7.3^ 0 \ C$

The molality of the solution is:

$= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}$

Molar depression constant of solvent X, $K_f = 4.82 ^0 \ C/m$

Hence, using the elevation in boiling point;

the Vant'Hoff factor $i = \dfrac{\Delta T_f}{k_f \times m}$

$i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}$

$\mathbf {i = 1.51 }$

3 0

3 years ago

A student has an unknown sample. How can spectroscopy be used to identify the sample?

iogann1982 [59]

Answer: A. It can identify the elements in the sample.

Explanation: on edge

4 0

4 years ago

The central core of an atom is called the __?

PilotLPTM [1.2K]

Answer: Atomic Nucleus!

Explanation: All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge.

(Yes, it was from google.)

6 0

3 years ago