Answer:
It's obviously true
Explanation:
As we have evolved over the years we have become more advanced
Answer:
2-4 mm height of capillary tube.
Explanation:
Sample should be around 2-4 mm in height.
It should be packed well so that it does not have air packets that caues the lowering of melting point.
If you take greater amount, then there will be needed more heat, resulting a wide range of melting point.
Answer :
According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.
The balanced chemical reaction is,

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of
is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.
From the given balanced reaction, we conclude that
As, 1 mole of magnesium react
mole of oxygen to give 1 mole of magnesium oxide.
So, the mass of Mg is 24 g, the mass of
and the mass of MgO is 40 g.
That means 24 g of Mg react with 16 g
to give 40 g of MgO.
Answer:
Following are the responses to the given question:
Explanation:
Since HN03 is an oxidation substance D-ribose u.ith oxidized to form in rubric acid Ribose is chiral, but rubric acid is achiral because of its symmetry mirror level, Hence no infrared roster in the sample holder is observed.
Please find the attached file.
D-Arabinose, on either hand, gives optical aldaric acid with such a net optical rotation observed inside the polarimeter for diagnosis with HN03.
Answer:
RADIATION <em>is</em><em> </em><em>the</em><em> </em><em>transfer</em><em> </em><em>of</em><em> </em><em>Heat</em><em> </em><em>energy</em><em> </em><em>through</em><em> </em><em>space</em><em> </em><em>by</em><em> </em><em>Electromagnetic</em><em> </em><em>Radiation</em><em>.</em><em> </em><em>Most</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>electromagnetic</em><em> </em><em>radiation</em><em> </em><em>that</em><em> </em><em>comes</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>earth</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>Sun</em><em> </em><em>is</em><em> </em><em>invisible</em><em>.</em>