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Gekata [30.6K]
3 years ago
13

Use this diagram to determine which of the following statements is true.

Chemistry
1 answer:
natima [27]3 years ago
3 0

Answer:

D. Catalysts speed up the rate of reactions by lowering the amount of energy required for the reaction to proceed.

Explanation:

A catalyst is a substance that:

  • speeds up the rate of a reaction .
  • does not alter the products of the reaction .
  • is unchanged chemically and in mass at the end of the reaction.

<em>A catalyst provides an alternative reaction pathway that has a lower activation energy than the uncatalyzed reaction. </em>

<em></em>

The figure shows how the energy of the reactants and products change during a reaction.

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Marina86 [1]

Answer:

solid change directly into a vapor in the process known simply as freezing

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How many molecules are in 2.00 moles of H20????????
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2x 6.022x10^23= 1.204x10^24

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When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2
MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is \Delta \ T_f = T_{solvent}- T_{solution}

\Delta \ T_f = 2.9 ^0 \ C

Using the depression in freezing point, the molar depression constant of the solvent K_f = \dfrac{\Delta T_f}{m}

K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}

K_f = 4.82 ^0 C / m}

The freezing point of the solution \Delta T_f = T_{solvent} - T_{solution}

\Delta T_f = 7.3^ 0 \ C

The molality of the solution is:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

Molar depression constant of solvent X, K_f = 4.82 ^0 \ C/m

Hence, using the elevation in boiling point;

the Vant'Hoff factor i = \dfrac{\Delta T_f}{k_f \times m}

i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

3 0
3 years ago
A student has an unknown sample. How can spectroscopy be used to identify the sample?
iogann1982 [59]

Answer: A. It can identify the elements in the sample.

Explanation: on edge

4 0
4 years ago
The central core of an atom is called the __?
PilotLPTM [1.2K]

Answer: Atomic Nucleus!

Explanation: All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge.

(Yes, it was from google.)

6 0
3 years ago
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