Answer:
unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]
Explanation:
Given:
v = (-23.2, -104.4, 46.4) m/s
Above expression describes spacecraft's velocity vector v.
Find:
Find unit vector in the direction of spacecraft velocity v.
Solution:
Step 1: Compute magnitude of velocity vector.
mag (v) = sqrt ( 23.2^2 + 104.4^2 + 46.4^2)
mag (v) = 116.58 m/s
Step 2: Compute unit vector unit (v)
unit (v) = vec (v) / mag (v)
unit (v) = [ -23.2 i -104.4 j + 46.4 k ] / 116.58
unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]
Answer:
9 volts (assuming 0.60 is in Amperes)
Explanation:
Recall that Ohms law can be expressed as
V = IR, where
V = voltage,
I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)
R = resistance (given as 15 ohm)
substituting the above values into the formula
V = IR
V = (0.6)(15)
V = 9 Volts
True since coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.
<h3>What is the coulombs law ?</h3>
coulombs formula is given by
![F= \dfrac{K\times q_{1} \times q_{2}}{r^{2} }](https://tex.z-dn.net/?f=F%3D%20%20%5Cdfrac%7BK%5Ctimes%20q_%7B1%7D%20%5Ctimes%20q_%7B2%7D%7D%7Br%5E%7B2%7D%20%7D)
Now it states that if two charged particles are separated by the distance r and having same or opposite charge will attract or repel each other.
The intensity of the force depend upon the distance and the nature of the charge.
Hence coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.
To know more about coulomb's law follow
https://brainly.in/question/332179
Answer:
Density of 18.0-karat gold mixture is
.
Explanation:
A mixture of 18 parts gold, 5 parts silver, and 1 part copper.
Let mass of gold be 18x
Let the mass of silver be 5x
Let the mass of copper be 1x
The density of gold = ![19.32g/cm^3](https://tex.z-dn.net/?f=19.32g%2Fcm%5E3)
The density of silver = ![10.1g/cm^3](https://tex.z-dn.net/?f=10.1g%2Fcm%5E3)
The density of copper =![8.8g/cm^3](https://tex.z-dn.net/?f=%208.8g%2Fcm%5E3)
![Volume=\frac{Mass}{Density}](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7BMass%7D%7BDensity%7D)
Volume of the gold in the mixture = ![V_1=\frac{18x}{19.32 g/cm^3}](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7B18x%7D%7B19.32%20g%2Fcm%5E3%7D)
Volume of the silver in the mixture = ![V_2=\frac{5x}{10.1 g/cm^3}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B5x%7D%7B10.1%20g%2Fcm%5E3%7D)
Volume of the copper in the mixture = ![V_3=\frac{1x}{8.8 g/cm^3}](https://tex.z-dn.net/?f=V_3%3D%5Cfrac%7B1x%7D%7B8.8%20g%2Fcm%5E3%7D)
Mass of the mixture = M = 18x+5x+1x =24x
Volume of the mixture = ![V_1+V_2+V_3](https://tex.z-dn.net/?f=V_1%2BV_2%2BV_3)
Density of the mixture:
![\frac{M}{V_1+V_2+V_3}=15.58 g/cm^3](https://tex.z-dn.net/?f=%5Cfrac%7BM%7D%7BV_1%2BV_2%2BV_3%7D%3D15.58%20g%2Fcm%5E3)