Answer:
gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave
Explanation:
given light form,
A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays
we know,
wavelength of radio wave = 10000 Km
wavelength of infrared = 700 nanometers (nm) to 1 millimeter (mm)
wavelength of visible light = 380 to 740 nm
wavelength of ultraviolet ray = 10 nm to 400 nm
wavelength of X-ray = 0.01 to 10 nm
wavelength of gamma rays = 100 picometer
so, the order of rays.
gamma rays < X-ray < ultraviolet ray < visible light < infrared < radio wave
Answer:
Option B is the correct answer.
Explanation:
Shear stress is the ratio of shear force to area.
We have
Shear stress = 3 N/mm² = 3 x 10⁶ N/m²
Area = Area of rectangle = 10 x 10⁻² x d = 0.1d
Shear force = 50000 N
Substituting

Width of beam = 16.67 cm
Option B is the correct answer.
Electric potential energy of a dipole is given as


so change in the potential energy is given by


here initially it was parallel to electric field while finally it is perpendicular to the electric field
so we have


so above is the change in potential energy of dipole
Answer:
acceleration due to gravity: -9.8 m/s^2
Fg=mass of object*(-9.8)
Explanation:
This is a pretty vague question, but I'll answer as best I can.
All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as
Force of gravity=(Gravitational constant*mass of object 1*mass of object 2)/distance between objects squared
Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)
Answer:
j
Explanation:
x = 4 t^2 - 2 t - 4.5
Position at t = 3 s
x = 4 (3)^2 - 2 (3) - 4.5 = 25.5 m
Velocity at t = 3 s
v = dx / dt = 8 t - 2
v ( t = 3 s) = 8 x 3 - 2 = 22 m/s
Acceleration at t = 3 s
a = dv / dt = 8
a ( t = 3 s ) = 8 m/s^2
When is the velocity = 0
v = 0
8 t - 2 = 0
t = 0.25 second
When is the position = 0
x = 0
4 t^2 - 2 t - 4.5 = 0

t = 1.4 second