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aleksandrvk [35]
3 years ago
12

Nitrogen can ionically bond with an unknown element X from group 2. How many ions of element X are required to create a stable i

onic compound with nitrogen?
Question 15 options:


2


03


4


There is not enough information
Chemistry
2 answers:
Nataliya [291]3 years ago
8 0
I can tell you there certainly is enough information, so we can eliminate the fourth option right away.
Group two elements tend to form 2+ cations, and nitrogen forms 3- anions. To make a stable substance, we need those to cancel out. Calling the group 2 element X:
N2X3 would cause the charge to be 2(-3) + 3(2) = 0
This would mean 3 ions of X and 2 anions of N would be a stable ionic compound.
torisob [31]3 years ago
3 0

Answer:

B.) 3

Explanation:

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Leni [432]
The answer is: Graphite
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3 years ago
What is the mass in grams of a single formula unit of silver chloride, AgCI? A) 4.21 x 1021 g B) 8.61 x 10258 C) 1.66 x 10-248 D
bekas [8.4K]

Answer: D) 2.38*10^-^2^2 g

Explanation: The question asks to convert formula unit to grams. It is a unit conversion problem.

1 mole equals to Avogadro number of formula units. So, to convert the given number of formula units to moles, we need to divide by the Avogadro number. After this, we do moles to grams conversion and for this the moles are multiplied by the molar mass of the compound. Molar mass of AgCl is 143.32 gram per mol.

1FormulaUnitAgCl(\frac{1mol}{6.022*10^2^3formulaUnits})(\frac{143.32g}{1mol})

= 2.38*10^-^2^2 g

So, the correct option is D) 2.38*10^-^2^2 g

7 0
3 years ago
Read 2 more answers
This question in the screenshot
Morgarella [4.7K]

Mass of hydrate + crucible = 47.29 g

Mass of anhydrous salt = 2.7 g

Molar mass of anhydrous salt CuSO4 = 159.5 g

Given,

mass of empty crucible = 42.45 g

mass of hydrate salt= 4.84 g

mass of crucible after first heating = 46.1 g

mass of crucible after second heating= 45.153 g

mass of crucible after third heating= 45.15 g

so, as per the question we need to find...

Mass of hydrate + crucible = ? g

Mass of anhydrous salt = ? g

Molar mass of anhydrous salt CuSO4 = ? g

∴Mass of hydrate + crucible = 42.45 + 4.48 = 47.29 g

The given salt is in hydrate form, to remove water from this molecule we need to perform heating .

So we are taking the substance into the crucible as it is in less quantity.

Here, we performed heating 3 times and note the weight after every heating.

After this, assume that the water is totally evaporated and the remaining salt is in anhydrous form,

∴ Mass of anhydrous salt = 45.15 - 42.45 = 2.7 g

To find the molar mass of anhydrous salt of CuSO4,

atomic weight of Cu = 63.5 g

atomic weight of S = 32 g

atomic weight of O =16 g

∴ molar mass of anhydrous salt of CuSO4 = 63.5 + 32 + (16 ×3)

                                                                   =159.5 gm

Learn more about molar mass here...

brainly.com/question/837939

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5 0
2 years ago
What are the three isotopes of hydrogen and what is the significance of these isotopes?
antiseptic1488 [7]

Answer:

21H deuterium (D), 31H is tritium (T), 11H is hydrogen

Explanation:

11H: it has the greatest abundance, it has only one proton (it does not have neutrons).

 21H (D): it has a proton and a neutron in its nucleus.

 31H (T): it has a proton and two neutrons in its nucleus.

Remember that isotopes have the same atomic number, but a different mass number (elements in the number of neutrons differed).

4 0
3 years ago
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192 grams of (NH 4 ) 2 CO 3 (N Molar Mass : 96g ) are dissolved to make 2150 mL of solution , what is the concentration of this
svlad2 [7]

The concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M. Details about concentration can be found below.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

no of moles of NH42CO3 = 192g ÷ 96g/mol = 2 mol

Concentration of solution = 2 moles ÷ 2.15L

Concentration of solution = 0.93M

Therefore, the concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M.

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4 0
2 years ago
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