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densk [106]
3 years ago
7

1. ¿Cuál es el aporte a la electrostática que se le atribuye a Thales de Mileto?

Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer: Descubrio una forma de observar la corriente estática, y quizas fue uno de los primeros en observarla y escribir sobre ella.

Explanation:

Alrededor del 600 a.C. Tales se da cuenta de que frotando pieles con otros materiales, lograba que estos atrajeran motas de polvo, y luego escribió sobre esto que hoy en día conocemos como electricidad estática. De hecho los romanos descubrieron que frotando pieles con ámbar podían ver como pequeñas chispas saltando de estos.

Esto sucede por que al frotar los dos materiales, uno de ellos tiene tendencia a perder cargas mientras el otro (usualmente conductor o aislante) tendrá tendencia a absorberlos. Luego esas cargas absorbidas son una corriente estática que queda "almacenada" en uno de los materiales.

Entonces podemos decir que el aporte a la electrostática que se le atribuye a Tales de Mileto es "descubrir" la electricidad estática.

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I hope I've helped! :)

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Anyone knows this? Please answer... Spam will be reported.
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Answer:

The correct option is;

The assertion is correct, but reason wrong

Explanation:

The question is with regards to the relationship between work, energy, power, and velocity

The mass of each of the persons running up the staircase = Different

The time it takes each person to run up the stairs = Equal time

Let, 'm₁' and 'm₂' represent the mass of each of the persons that ran up the stairs and m₁ > m₂

Let 't' represent the equal time it takes then to run up the stairs

Let 'h' represent the height of the stairs

The energy, 'E', it takes to run up the stairs is equal to the potential energy, P.E., obtained at the top of the stairs

P.E. = m·g·h

Where;

m = The mass of the person at an elevated height

g = The acceleration due to gravity = Constant

h = The height reached above ground level

Given that the height reached is the same for both of the persons, we have

For m₁, P.E.₁ = m₁·g·h and for m₂, P.E.₂ = m₂·g·h

Therefore, where, m₁ > m₂, we have;

P.E.₁ > P.E.₂

∴ E₁ > E₂

Power, 'P', is the rate at which energy is expended

∴ Power, P = E/t

∴ P₁ = E₁/t  > P₂ = E₂/t

Therefore, the person with the greater mass, 'm₁', uses more power than the person of mass 'm₂', in running up the stairs

Therefore, the assertion is correct

The average velocity, vₐ = (Total distance traveled, d)/(Total time taken, t)

Given that the distance, 'd', covered in running up the stairs by both persons is the same, and the time it takes them to complete the distance, 't', is also the same, we have;

The average velocity of the person with the greater mass m₁ is the same as the average velocity of the person with mass, m₂

Therefore, the reason is wrong

The answer is that the assertion is correct, but reason wrong

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