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Answer:
ΔT =
Explanation:
In a simple harmonic motion, specifically in the simple pendulum, the angular velocity
w =
angular velocity and period are related
w = 2π / T
we substitute
2π / T = \sqrt{\frac{g}{L} }
T =
In this exercise indicate that for a long Lo the period is To, then and increase the long
L = L₀ + ΔL
we substitute
T =
T =
in general the length increments are small ΔL/L «1, let's use a series expansion
we keep the linear term, let's substitute
T =
if we do
T = T₀ + ΔT
T₀ + ΔT =
T₀ + ΔT = T₀ +
ΔT =