Answer:
200 N/m
20 rad/s
0.31415 seconds
3.18309 Hz
Explanation:
m = Mass of glider = 0.5 kg
x = Displacement of spring
F = Force on spring = 6 N
From Hooke's law we have relation
![F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{6}{0.03}\\\Rightarrow k=200\ N/m](https://tex.z-dn.net/?f=F%3Dkx%5C%5C%5CRightarrow%20k%3D%5Cfrac%7BF%7D%7Bx%7D%5C%5C%5CRightarrow%20k%3D%5Cfrac%7B6%7D%7B0.03%7D%5C%5C%5CRightarrow%20k%3D200%5C%20N%2Fm)
The spring constant is 200 N/m
Angular frequency is given by
![\omega=\sqrt{\frac{k}{m}}\\\Rightarrow \omega=\sqrt{\frac{200}{0.5}}\\\Rightarrow \omega=20\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D%5C%5C%5CRightarrow%20%5Comega%3D%5Csqrt%7B%5Cfrac%7B200%7D%7B0.5%7D%7D%5C%5C%5CRightarrow%20%5Comega%3D20%5C%20rad%2Fs)
The angular frequency is 20 rad/s
Frequency is given by
![f=\frac{\omega}{2\pi}\\\Rightarrow f=\frac{20}{2\pi}\\\Rightarrow f=3.18309\ Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B%5Comega%7D%7B2%5Cpi%7D%5C%5C%5CRightarrow%20f%3D%5Cfrac%7B20%7D%7B2%5Cpi%7D%5C%5C%5CRightarrow%20f%3D3.18309%5C%20Hz)
The frequency is 3.18309 Hz
Time period is given by
![T=\frac{1}{f}\\\Rightarrow T=\frac{1}{3.18309}\\\Rightarrow T=0.31415\ s](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B1%7D%7Bf%7D%5C%5C%5CRightarrow%20T%3D%5Cfrac%7B1%7D%7B3.18309%7D%5C%5C%5CRightarrow%20T%3D0.31415%5C%20s)
The time period is 0.31415 seconds
Answer:
30 miles people hour (mph)
Explanation:
The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.