Answer:
The magnitude of the electric field is 1.124 X 10⁷ N/C
Explanation:
Magnitude of electric field is given as;
where;
E is the magnitude of the electric field, N/C
q is the point charge, C
k is coulomb's constant, Nm²/C²
r is the distance of the point charge, m
Given;
q = 5mC = 5×10⁻³ C
r = 2m
k = 8.99 × 10⁹ Nm²/C²
Substitute these values and solve for magnitude of electric field E
Therefore, the magnitude of the electric field is 1.124 X 10⁷ N/C
BecausE the first 'a' is used with a 'u' making a "ahh" sound
The second 'a' isn't paired with any other vowels so it's sound is a strong A sound
And the 'a' at the end is paired with an 'i' in front of it making an "ee-uhh" sound
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A infared light has a higher
The answer is D
This is an example of Newton's third law of motion.
The active force is the fish against the water, so the reactive force would be the reverse, the equal force of the water on the fish.
