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brilliants [131]
4 years ago
7

The superheroine Xanaxa, who has a mass of 68.1 kg , is pursuing the 75.3 kg archvillain Lexlax. She leaps from the ground to th

e top of a 193 m high building then dives off it and comes to rest at the bottom of a 16.1 m deep excavation where she finds Lexlax and neutralizes him. Does all this bring about a net gain or a net loss of gravitational potential energy?
Physics
1 answer:
Alexandra [31]4 years ago
4 0

The concept required to solve this problem is associated with potential energy. Recall that potential energy is defined as the product between mass, gravity, and change in height. Mathematically it can be described as

U = mg\Delta h

Here,

\Delta h = Change in height

m = mass of super heroine

g = Acceleration due to gravity

The change in height will be,

\Delta h = h_f - h_i

The final position of the heroin is below the ground level,

h_f = -16.1m

The initial height will be the zero point of our system of reference,

\Delta h = -16.1m-0m

\Delta h = -16.1m

Replacing all this values we have,

U = mg\Delta h

U = (68.1kg)(9.8m/s^2)(-16.1m)

U = -10744.81J

Since the final position of the heroine is located below the ground, there will net loss of gravitational potential energy of 10744.81J

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A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin return
tensa zangetsu [6.8K]

Answer:

1.68 s

Explanation:

From newton's equation of motion,

a = (v-u)/t.................................. Equation 1

Making t the subject of the equation

t =(v-u)g............................. Equation 2

Where t = time taken for the bowling pin to reach the maximum height, v = final velocity bowling pin, u = initial velocity of the bowling pin, g = acceleration due to gravity.

Note: Taking upward to be negative and down ward to be positive,

Given: v = 0 m/s ( at the maximum height), u = 8.20 m/s, g = -9.8 m/s²

t = (0-8.20)/-9.8

t = -8.20/-9.8

t = 0.84 s.

But,

T = 2t

Where T = time taken for the bowling pin to return to the juggler's hand.

T = 2(0.84)

T = 1.68 s.

T = 1.68 s

7 0
3 years ago
Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in se
ASHA 777 [7]

Answer:

R = 9.85 ohm , r = 0.85 ohm

Explanation:

Let the two resistances by r and R.

when they are connected in series:

V = 12 V

i = 1.12 A

The equivalent resistance when they are connected in series is

Rs = r + R

So, By using Ohm's law

V = i Rs

Rs = V / i = 12 / 1.12 = 10.7 ohm

R + r = 10.7 ohm    .... (1)

When they are connected in parallel:

V = 12 V

i = 9.39 A

The equivalent resistance when they are connected in parallel

R_{p}=\frac{R+r}{rR}

So, By using Ohm's law

V = i Rp

Rp = V / i = 12 / 9.39 = 1.28 ohm

\frac{R+r}{rR}=1.28    .... (2)

by substituting the value of R + r from equation (1) in equation (2), we get

r R = 8.36 ..... (3)

R-r = \sqrt{\left ( R+r \right )^{2}-4rR}

R-r = \sqrt{\left ( 10.7 \right )^{2}-4\times 8.36}=9 ..... (4)

By solvng equation (1) and (4), we get

R = 9.85 ohm , r = 0.85 ohm

8 0
3 years ago
A narrow region between two air masses of different densities is a
Sav [38]
A front is a narrow region  between two air masses of different densities.
5 0
3 years ago
How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
DedPeter [7]

Answer:

100 Watts

Explanation:

<u>These equations are needed to work out the answer:</u>

  • power= work done/ time taken
  • work done= force* distance
  • force= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

7 0
3 years ago
How is the rotation of the sun, different from the rotation of the earth
vesna_86 [32]

Answer:

The Sun has a north and south pole, just as the Earth does, and rotates on its axis. However, unlike Earth which rotates at all latitudes every 24 hours, the Sun rotates every 25 days at the equator and takes progressively longer to rotate at higher latitudes, up to 35 days at the poles. This is known as differential rotation.

Explanation:

6 0
3 years ago
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