The initial horizontal velocity of the rock, in m/s is 21.241 m/s.
<h3>What is projectile?</h3>
When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Time taken by the stone to reach the ground is
t = √2h/g
t = √(2x 86)/9.81
t = 4.19s
The horizontal velocity is
V(x) = Horizontal distance traveled / Time taken t
Put the values, we get
V(x) = 89 m/4.19 s
V(x) = 21.241 m/s
Thus, the horizontal velocity is 21.241 m/s
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The answer is D.
I hope this helps.
M = mass of the whale = 1000 kg
m = mass of the seal = 200 kg
V = initial velocity of whale before collision with the seal = 6.0 m/s
v = initial velocity of the seal before collision with the whale = 0 m/s
V' = final velocity of two sea creatures after collision = ?
Using conservation of momentum
M V + m v = (M + m) V'
inserting the above values in the equation
(1000 kg) (6.0 m/s) + (200 kg) (0 m/s ) = (1000 kg + 200 kg) V'
6000 kgm/s + 0 kgm/s = (1200 kg) V'
V' = (6000 kgm/s ) /(1200 kg)
V' = 5 m/s
F=ma
f=4.5*9
40.5 N
hope this help
