Answer:
a)14.17V
b)32.8 x 
J
c)96.9x J
d) -64x J
Explanation:
Given:
Area 'A'=7.10cm² =>7.1 x 
m²
voltage '
'=4.8 volt
= 2.20mm => 2.2 x 
m
= 6.50mm => 6.5 x m
a) Capacitance 
before push is given by:
= εA/ =>
= 2.85 x F
==> 2.85 x x 4.8
=1.37 x 
C
Capacitance 
after push is given by:
= εA/ =>
= 9.66 x 
F
=
=
Therefore, the potential difference between the plates
= 1.37 x / 9.66 x =>14.17V
b) 
32.8 x J
c)
= 96.9x J
d) the work required to separate the plates is given by:
workdone= 
-=> 32.8 x J- 96.9x J
W≈ -64x J
Answer:
ΔH°comb=-5899.5 kJ/mol
Explanation:
First, consider the energy balance:
Where 
is the calorimeter mass and 
is the number of moles of the samples; 
is the combustion enthalpy. The energy balance says that the energy that the reaction release is employed in rise the temperature of the calorimeter, which is designed to be adiabatic, so it is suppose that the total energy is employed rising the calorimeter temperature.
The product 
is the heat capacity, so the balance equation is:
So, the enthalpy of combustion can be calculated:
I will be happy to solve any doubt you have.
I believe the answer is a
Kinetic Energy,K.E=1/2MV²
mass,m=16kg
velocity,v=4m/s
K.E=1/2×16×4²
=128kgm²/s²
=128 Joules
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