Answer:
The half life for radioactive can be calculated as:
N /N0 = (1 /2) ^ n
n = T /T half
According to question there are n number of half life are present which would result in remaining amount of element as n.
Explanation:
Sorry if wrong
Answer:
woodpecker it's easy lil lol
Explanation:
This is a neutral beryllium atom
Answer:
cis-1-tert-butyl-3-methylcyclohexane will have a higher percentage of the diequatorial-substituted conformer when compared with the diaxialsubstituted conformer.
Explanation:
The two compound contain or have high stability with the substituent group is at equatorial position but the tert-betyl group in cis-1-tert-butyl-3-methylcyclohexane is larger than the methyl group in trans-1,4-dimethylcyclohexane.
Thus, the equatorial position will be more favorable for the substituent group in the cis-1-tert-butyl-3-methylcyclohexane, therefore having higher percentage of the diequatorial substituted conformer compared with that of diaxial-substituted conformer.
Answer:
Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.
Explanation: