Answer:

Explanation:
From similar question, equation (b) is
Molecular Equation:
- Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)
Net Ionic Equation:
- Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s)
<u>1. Mole ratio:</u>

<u>2. Convert 1.147 g of Cu(s) to moles:</u>
- Atomic mass of Cu: 63.546g/mol
- Number of moles = mass in grams / atomic mass
- Number of moles = 1.147 g / 63.546 g/mol = 0.01805 mol Cu(s)
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<u>3. Calculate the moles of Ag(s):</u>

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<u>4. Convert 0.03610 mol Ag(s) to grams:</u>
- Atomic mass of Ag(s) = 107.868g/mol
- Mass = 0.03610mol × 107.868g/mol = 3.894g
Given :
Chlorine's 3p sub level has 5 electrons in it.
To Find :
How many electron(s) more in the 3p sub-level to make it stable.
Solution :
Electronic configuration of Chlorine is :
[Ne] 3s² 3p⁵.
We know, p-orbit is stable with 6 electronic.
Therefore, to stable p-orbit 1 more electron is required in 3p sub-level.
Hence, this is the required solution.
The answer is Mercury sulfide, it is composed of the elements mercury and sulfur.
Answer:
Effect of Hybridisation on Single, Double and Triple Bond Lengths of Carbon. Since the sp hybrid orbital contains more s-character (50%), it is closer to its nucleus; therefore, it forms shorter bonds. Because of the same reason sp2 hybrid orbital forms shorter bonds than sp3 hybrid orbitals.