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Sonja [21]
3 years ago
12

A substance releases 2,192 J of heat, changing its temperature from 50 degrees C to 5 degrees C. The mass of the substance is 73

.9 grams. What is the specific heat of the substance? Round your answer to TWO digits after the decimal point.
Chemistry
1 answer:
Gre4nikov [31]3 years ago
3 0

The specific heat capacity of the given substance is -0.66 J/g°C.

<u>Explanation:</u>

The heat absorbed by any substance is the product of its mass, specific heat capacity and change in temperature.

q = m × c × ΔT

m is the mass in grams

q = amount of heat released or absorbed in J

ΔT = change in temperature in °C = 5 -50 = -45°C

c = specific heat capacity in J/g°C

c = $\frac{q}{m \times dT}

Plugin the values, we will get,

c = $\frac{2192 }{73.9 \times-45}

= -0.66 J/g°C

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Wind between 39-46 mph can cause branches and limbs to break, make it hard for cars to stay on the road wind between 47-54 can cause lighting difficulties, wind between the 60-78 can cause trees to uproot and damage.

Explanation:

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3 years ago
Writing the net ionic equation
vazorg [7]

First write the molecular equation with states:


(NH4)2S (aq) + 2AgNO3(aq) → Ag2S (s) + 2NH4NO3


Now write a full ionic equation by separating into ions all substances that dissociate: anything (s) (g) or (l) does not dissociate


2NH4 + (aq) + S 2-(aq) + 2Ag+ (aq) + 2NO3- (aq) → Ag2S(s) + 2NH4 + (aq) + 2NO3- (aq)


To write the NET IONIC equation, inspect the full ionic equation above and delete anything that appears on both sides of the → sign:


Net ionic equation:

S 2-(aq) + 2Ag + (aq) → Ag2S(s)

3 0
3 years ago
Read 2 more answers
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

3 0
3 years ago
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How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?
nalin [4]

Answer:

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

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3 years ago
When calcium oxide, CaO(s) dissolves in water, the water becomes hot. Write a chemical equation for this process and indicate wh
denis23 [38]

Answer:

The interaction reaction of calcium oxide and water leads to the formation of calcium hydroxide, this reaction is exothermic, which indicates that energy is released.

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Explanation:

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