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Andrew [12]
3 years ago
13

Methanol, ethanol, and n−propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is lib

erated as indicated. Calculate the heats of combustion of these alcohols in kJ/mol.
Chemistry
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

<u>For methanol:</u> Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)

<u>For ethanol: </u>Heat of combustion = -29.7 kJ / 0.0217 moles = -1368.6636 kJ/mol (negative sign signifies release of heat)

<u>For propanol: </u>Heat of combustion = -33.4 kJ / 0.0166 moles = -2012.0482 kJ/mol (negative sign signifies release of heat)

Explanation:

Given:

Mass of Methanol = 1.0 g

Mass of ethanol = 1.00 g

Mass of n-propanol = 1.00 g

<u>For methanol:</u>

2 CH₃OH + 3 O₂ ----> 2 CO₂ + 4 H₂O, ∆H₀ = -22.6 kJ/g  (negative sign signifies release of heat)

1 g of methanol on combustion gives 22.6 kJ of energy

Calculation of moles of methanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of methanol = 32.04 g/mol

Thus moles of methanol = 1 g/ (32.04 g/mol) = 0.0312 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)</u>

<u></u>

<u>For ethanol:</u>

C₂H₅OH + 3 O₂ ----> 2 CO₂ + 3 H₂O, ∆H₀ = -29.7 kJ/g  (negative sign signifies release of heat)

1 g of ethanol on combustion gives 29.7 kJ of energy

Calculation of moles of ethanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of ethanol = 46.07 g/mol

Thus moles of ethanol = 1 g/ (46.07 g/mol) = 0.0217 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -29.7 kJ / 0.0217 moles = -1368.6636 kJ/mol (negative sign signifies release of heat)</u>

<u></u>

<u>For propanol:</u>

2 C₃H₇OH + 9 O₂ ----> 6 CO₂ + 8 H₂O, ∆H₀ = -33.4 kJ/g , (negative sign signifies release of heat)

1 g of methanol on combustion gives 33.4 kJ of energy

Calculation of moles of methanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of methanol = 60.09 g/mol

Thus moles of methanol = 1 g/ (60.09 g/mol) = 0.0166 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -33.4 kJ / 0.0166 moles = -2012.0482 kJ/mol (negative sign signifies release of heat)</u>

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Lisa [10]

Answer:

1. The empirical formula is CH2O

2. The molecular formula is C6H12O6

Explanation:

Data obtained from the question include:

Carbon (C) = 48.38g

Hydrogen (H) = 8.12g

Oxygen (O) = 53.5g

Molar Mass of the compound = 180.15 g/mol

1. The empirical formula can be obtained as follow:

C = 48.38g

H = 8.12g

O = 53.5g

Divide each by their molar mass

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H = 8.12/1 = 8.12

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Next, divide by the smallest

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O = 3.344/3.344 = 1

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2. The molecular formula is mostly a multiple of the empirical i.e

Molecular formula => [CH2O]n

Now, we need to find the value of 'n' in order to obtain the molecular formula.

From the question given, we were told that the molar mass of the compound is 180.15 g/mol. With this information, the molecular formula can be obtained as follow:

[CH2O]n = 180.15

[12 + (2x1) + 16]n = 180.15

[12 + 2 + 16]n = 180.15

30n = 180.15

Divide both side by the coefficient of n i.e 30

n = 180.15/30

n = 6

Therefore, the Molecular formula is

=> [CH2O]n

=> [CH2O]6

=> C6H12O6

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