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Inga [223]
3 years ago
15

You have a cold gas of atoms, and you observe that if you shine light consisting of photons with energy 10 eV through the gas, s

ome free electrons are observed, implying that a photon of this energy is able to ionize an atom in the gas. (a) If you find that the emitted electrons from the gas have a kinetic energy of 1 eV, what is the ionization energy of the cold atom
Chemistry
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

Ionization Energy = 9 eV

Explanation:

If we apply the law of conservation of energy to the given situation, we will get the following equation:

Energy\ of\ Photon = Ionization\ Energy + Kinetic\ Energy\ of\ Electron\\

where,

Energy of Photon = 10 eV

Ionization Energy = ?

Kinetic Energy of Electrons = 1 eV

Therefore,

10\ eV = Ionization\ Energy + 1\ eV\\Ionization\ Energy = 10\ eV - 1\ eV

<u>Ionization Energy = 9 eV</u>

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pyrite is a mineral composed of 46.5 mass % iron and 53.5 mass % sulfur. determine the empirical formula for calcocite.
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The empirical formula for pyrite is FeS2.

HOW TO CALCULATE EMPIRICAL FORMULA:

  • The empirical formula represents the simplest whole number ratio of constituents element of a compound. The empirical formula of pyrite can be calculated as follows:

46.5 mass % Fe = 46.5g of Fe

53.5 mass % S = 53.5g of S

  • Next, we divide each element's mass value by its molar mass

Fe = 46.5g ÷ 56g/mol = 0.83mol

S = 53.5g ÷ 32g/mol = 1.67mol

  • Next, we divide each mole value by the smallest (0.83mol)

Fe = 0.83mol ÷ 0.83 = 1

S = 1.67mol ÷ 0.83 = 2.014

Approximately, the ratio of Fe to S is 1:2. Therefore, the empirical formula of pyrite is FeS2.

Learn more at: brainly.com/question/14044066?referrer=searchResults

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