Explanation:
303k -273k=30°c because 0°c is 273K
<span> Speicific heat of water is 4.2j/gm*C </span>
<span>Thus 4.2 Joules of energy is required to heat 1 gm water to 1*C. </span>
<span>or 4.2 x 30 Joules enery is required to heat 1x30 gm water by 1*C </span>
<span>or 4.2 x 30 x 80 Joules enery is required to heat 1 x 30 gm water by (100-20)*C( or required to be removed from water to cool it) </span>
First you must write a balanced chemical equation.
C3H8 + 5O2 --> 3CO2 + 4H2O
From there, we can set up the stoichiometry equation to solve.
g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)
Now solve, and you should get 254.7 g O2. Hope this helped!
Density. water's density is always 1 g/ cm^3
