It should be 3.36 g / min but i m not sure
Answer:
Rate of forward reaction will increase.
Explanation:
Effect of change in reaction condition on equilibrium is explained by Le Chatelier's principle. According to this principle,
If an equilibrium condition of a dynamic reversible reaction is disturbed by changing concentration, temperature, pressure, volume, etc, then reaction will move will in a direction which counteract the change.
In the given reaction,
A + B ⇌ C + D
If concentration of A is increase, then reaction will move in a direction which decreases the concentration of A to reestablish the equilibrium.
As concentration A decreases in forward direction, therefore, rate of forward reaction will increase.
Answer: Option (A) is the correct answer.
Explanation:
Chemical equation for the given reaction is as follows.

And, the expression to calculate pH of this reaction is as follows.
pH = ![pk_{a} + log \frac{[HCOO^{-}]}{[HCOOH]}](https://tex.z-dn.net/?f=pk_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BHCOO%5E%7B-%7D%5D%7D%7B%5BHCOOH%5D%7D)
As the concentration of
is directly proportional to pH. Hence, when there occurs a decrease in the pH of the solution the
will also decrease.
Thus, we can conclude that the statement, HCOO will accept a proton from HCl to produce more HCOOH and
, best supports the student's claim.
Answer:
15.9 g
Explanation:
(Take the atomic mass of C=12.0, H=1.0, O=16.0)
no. of moles = mass / molar mass
no. of moles of octane used = 11.2 / (12.0x8 + 1x18)
= 0.0982456 mol
Since oxygen is in excess and octane is the limiting reagent, the no. of moles of H2O depends on the no. of moles of octane used.
From the balanced equation, the mole ratio of octane : water = 2:18 = 1: 9,
so this means, one mole of octane produced 9 moles of water.
Using this ratio, we can deduce that (y is the no. of moles of water produced):

y = 0.0982456x9
y= 0.88421 mol
Since mass = no. of moles x molar mass,
mass of water produced = 0.88421 x (1.0x2+16.0)
=15.9 g