In 1784, Benjamin Franklin made what may have been the first connection between volcanoes and global climate while stationed in Paris as the first diplomatic representative of the United States of America. He observed that during the summer of 1783, the climate was abnormally cold, both in Europe and back in the U.S. The ground froze early, the first snow stayed on the ground without melting, the winter was more severe than usual, and there seemed to be "a constant fog over all Europe, and [a] great part of North America."
I HOPE THAR HELPS IF NOT IM SORRY:(
What is your question can you show pictures?
Answer and Explanation:
- Should let force applied throughout horizontal direction become "F", as well as the displacement of that same sled, become "d." This same force's work seems to be "Fd."
- Presently, unless the mass would be doubled as well as the force is applied continues to remain the very same, the work used by the force to keep moving the sled by such the distance "d" would then remain the same.
So that the above seems to be the right answer.
To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.
By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,
![\epsilon = -A \times \frac{\Delta B}{\Delta t}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-A%20%5Ctimes%20%5Cfrac%7B%5CDelta%20B%7D%7B%5CDelta%20t%7D)
![\epsilon = -A \times (\frac{B_f-B_i}{t_f-t_i})](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-A%20%5Ctimes%20%28%5Cfrac%7BB_f-B_i%7D%7Bt_f-t_i%7D%29)
Where A is the area of the loop, B the magnetic field and t the time.
Replacing with our values we have that
![\epsilon = -(\pi (1.5*10^{-2})^2)(\frac{0-23*10^{-6}}{7*10^{-3}-0})](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%28%5Cpi%20%281.5%2A10%5E%7B-2%7D%29%5E2%29%28%5Cfrac%7B0-23%2A10%5E%7B-6%7D%7D%7B7%2A10%5E%7B-3%7D-0%7D%29)
![\epsilon = 2.3225*10^{-6}V](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%202.3225%2A10%5E%7B-6%7DV)
Therefore the thermal energy produced is given by
![E = P*t = \frac{\epsilon^2}{R}t](https://tex.z-dn.net/?f=E%20%3D%20P%2At%20%3D%20%5Cfrac%7B%5Cepsilon%5E2%7D%7BR%7Dt)
![E = \frac{(2.3225*10^{-6})^2}{8*10^{-6}}*(7*10^{-3})](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%282.3225%2A10%5E%7B-6%7D%29%5E2%7D%7B8%2A10%5E%7B-6%7D%7D%2A%287%2A10%5E%7B-3%7D%29)
![E = 4.719*10^{-9}J](https://tex.z-dn.net/?f=E%20%3D%204.719%2A10%5E%7B-9%7DJ)
The thermal energy produced in the loop is ![4.719*10^{-9}J](https://tex.z-dn.net/?f=4.719%2A10%5E%7B-9%7DJ)
Longitudinal studies primarily help discover the relationship between different variables that lack similar background information.