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Nikolay [14]
3 years ago
8

To increase power we need to?

Physics
2 answers:
Oxana [17]3 years ago
4 0
Add thrust, increase velocity, add a jet engine, and many more.

Hope this Helps! :)
Ymorist [56]3 years ago
3 0
Add more gasoline!
Hope this helps!

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What is a charge-coupled device (CCD), and how is it used in astronomy?
Sedaia [141]

Answer:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region

Explanation:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region where it can be modified like changing it to a electronic value.

In astronomy, high-powered telescopes can be used with CCD device image sensor cameras. The imaging system can concentrate for a number of hours on one place in space once the Earth's rotation synchronizes with the telescope.

6 0
3 years ago
HELP PLEASE...
skad [1K]
Ya because they’re are both 50 liters
7 0
2 years ago
Hazardous wastes are placed into categories to aid in _____.
torisob [31]
The waste that poses substantial or potential threats to public and environment health
Hazardous waste are actually defined as RCRA in 40 CFR 261 the the four hazardous traits are 
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reactivity 
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4 0
3 years ago
Read 2 more answers
Need help ASAPPPPPP will mark brainleast if right no links or im reporting
kykrilka [37]

Answer: Density--> the amount of mass in a  given volume

Boiling point: the tempeture when a liquid becomes gas

Conductivity: the ability of a subtance to transfer heat or electricety

Bouyant force: The upward force of an object in a liquid

soulibility: the ability of a subtance to disolve in  other.

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5 0
2 years ago
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A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
TiliK225 [7]

Answer:

E = 6.77 *10^{3} N/C

Explanation:

THE GIVEN sheet can be taken as two horizontal force  with surface charge density is

at one surface is ∈_1 = 95*10^ {-9} C/mm2

at oher surface is ∈_2= -25*10^{-9} C/mm2

the magnitude of electric field due to surface charge is given as\frac{∈}{2∈_O}

So, electric field at P (2 CM below from surface is) = E_1 +E_2

E = \frac{∈_1}{2∈_O} +\frac{∈_2}{2∈_O}

E = \frac{95*10^{-9} +25*10^{-9}}{2*8.85*10^{-12}}

E = 6.77 *10^{3} N/C

8 0
3 years ago
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