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Ad libitum [116K]

2 years ago

13

This property of matter describes the relationship of mass to volume?

1 answer:

DedPeter [7]2 years ago

7 0

Density is a physical property that describes the relationship between mass and volume. Density is the amount of matter in a given space, or volume.

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40 POINTS!!! PLEASE HELPP!!!

NeX [460]

Answer:

A

Explanation:

if it was B it would say from one to another to another

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2 years ago

Read 2 more answers

An atom with 9 protons, 11 electrons, and 10 neutrons has a net charge of

LiRa [457]

You find net charge by subtracting the number of electrons from the number of protons (since protons are positive and electrons are negative). 9 - 10 = -1

5 0

3 years ago

a bowling ball has a mass of 6 kilograms. a tennis ball has a mass of 0.06 kilogram. how much inertia does the bowling ball have

Andreyy89

Answer:

100 times

Explanation:

Since inertia is directly proportional to the mass of an object, the higher the mass the higher the inertia. In this case, 6 Kg is 100 times heavier than 0.06 Kg to imply The bowling ball has 100 times more inertia than the tennis ball because it has 100 times more mass

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3 years ago

3. A lady walks 15.0 meters east and then 20.0 meters north.

NemiM [27]

Answer:

a. 25m

b. 25m

c. 35m

Explanation:

Given the distances walked as 15m east and 20m north:

Using Pythagoras Theorem, we calculate displacement as:

$a^2+b^2=c2, a=15,b=-20\\\\15^2+20^2=c^2\\\\c=\sqrt{15^2+20^2}=\sqrt{625}\\\\c=25m$

Hence, the resultant displacement is 25m

b. The distance from her start point is obtained by drawing a straight line from her final point to her initial point.

Given the distances walked as 15m east and 20m north:

Using Pythagoras Theorem, we calculate displacement as:

$a^2+b^2=c2, a=15,b=-20\\\\15^2+20^2=c^2\\\\c=\sqrt{15^2+20^2}=\sqrt{625}\\\\c=25m$

Hence, she is 25m away from her starting point.

c. The distance traveled is calculated by summing the total distance walked:

$d=d_1+d_2\\\\=15+20\\\\=35m$

Hence, the total distance traveled is 35m

3 0

2 years ago

A motorcycle is travelling at a constant velocity of 30ms. The motor is in high gear and emits a hum of 700Hz. The speed of soun

timurjin [86]

Answer:

a) $T=1.43\times 10^{-3}\ s$

b) $d=0.0429\ m$

c) $\lambda=0.4857\ m$

d) $f_o=767.7\ Hz$

Explanation:

Given:

velocity of the sound from the source, $S=340\ m.s^{-1}$

original frequency of sound from the source, $f_s=700\ Hz$

speed of the source, $v_s=30\ m.s^{-1}$

(a)

We know time period is inverse of frequency:

Mathematically:

$T=\frac{1}{f}$

$T=\frac{1}{700}$

$T=1.43\times 10^{-3}\ s$

(b)

Distance travelled by the motorcycle during one period of sound oscillation:

$d=v_s.T$

$d=30\times 1.43\times 10^{-3}$

$d=0.0429\ m$

(c)

The distance travelled by the sound during the period of one oscillation is its wavelength.

$\lambda=\frac{S}{f}$

$\lambda=\frac{340}{700}$

$\lambda=0.4857\ m$

(d)

observer frequency with respect to a stationary observer:

<u>According to the Doppler's effect:</u>

$\frac{f_o}{f_s}= \frac{S+v_o}{S-v_s}$ ...........................(1)

where:

$f_o\ \&\ v_o$ are the observed frequency and the velocity of observer respectively.

Here, observer is stationary.

$\therefore v_o=0\ m.s^{-1}$

Now, putting values in eq. (1)

$\frac{f_o}{700}= \frac{340+0}{340-30}$

$f_o=767.7\ Hz$

5 0

3 years ago