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3 years ago

A circuit has a current of 3.6 A and a resistance of 5.0 Ω. What is the voltage applied to the circuit?

Physics

2 answers:

Inessa [10]3 years ago

7 0

The key formula ===> Voltage = (current) x (resistance)

Plug in the numbers given ===> Voltage = (3.6 A) x (5.0 ohms)

Dooda multiplication ===> Voltage = 18 volts

seraphim [82]3 years ago

5 0

Answer: The correct answer is 18 V.

Explanation:

The mathematical expression from Ohm's law is as follows:

V=IR

Here, V is the voltage, R is the resistance and I is the current.

It is given in the problem that A circuit has a current of 3.6 A and a resistance of 5.0 Ω.

Put R= 5 ohm and I= 3.6 A in the above expression.

V= (3.6)(5)

V=18 V.

Therefore, the value of voltage is 18 V.

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Answer:

In m/s^2:

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3 years ago

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3 years ago

Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87

marshall27 [118]

Answer:

a) $\lambda=0.935\ \textup{m}$

b) $f=36.19\approx 36\ \textup{Hz}$

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

$L= n\frac{\lambda}{2}$

where,

$\lambda$ = wavelength

on substituting the values, we get

$1.87= 4\times \frac{\lambda}{2}$

$\lambda=0.935\ \textup{m}$

b) Speed of the wave (v) in the string is given as:

$v =f\lambda$

also,

$v=\sqrt\frac{T}{(\frac{m}{L})}$

equating both the formula for 'v' we get,

$f\lambda=\sqrt\frac{T}{(\frac{m}{L})}$

on substituting the values, we get

$f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}$

$f=\frac{33.84}{0.935}$

$f=36.19\approx 36\ \textup{Hz}$

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3 years ago