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3 years ago

A circuit has a current of 3.6 A and a resistance of 5.0 Ω. What is the voltage applied to the circuit?

Physics

2 answers:

Inessa [10]3 years ago

7 0

The key formula ===> Voltage = (current) x (resistance)

Plug in the numbers given ===> Voltage = (3.6 A) x (5.0 ohms)

Dooda multiplication ===> Voltage = 18 volts

seraphim [82]3 years ago

5 0

Answer: The correct answer is 18 V.

Explanation:

The mathematical expression from Ohm's law is as follows:

V=IR

Here, V is the voltage, R is the resistance and I is the current.

It is given in the problem that A circuit has a current of 3.6 A and a resistance of 5.0 Ω.

Put R= 5 ohm and I= 3.6 A in the above expression.

V= (3.6)(5)

V=18 V.

Therefore, the value of voltage is 18 V.

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Read 2 more answers

A person is nearsighted with a far point of 75.0 cm. a. What focal length contact lens is needed to give him normal vision

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Complete Question

The complete question is shown on the first uploaded image

Answer:

$f= -75 \ cm = - 0.75 \ m$

$P = -1.33 \ diopters$

Explanation:

From the question we are told that

The image distance is $d_i = -75 cm$

The value of the image is negative because it is on the same side with the corrective glasses

The object distance is $d_o = \infty$

The reason object distance is because the object father than it being picture by the eye

General focal length is mathematically represented as

$\frac{1}{f} = \frac{1}{d_i} - \frac{1}{d_o}$

substituting values

$\frac{1}{f} = \frac{1}{-75} - \frac{1}{\infty}$

=> $f= -75 \ cm = - 0.75 \ m$

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$P = \frac{1}{f}$

substituting values

$P = \frac{1}{-0.75}$

$P = -1.33 \ diopters$

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